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Consider the Problem ut(x,0)=g(x)u _ { t } ( x , 0 ) = g ( x )

Question 13

Multiple Choice

Consider the problem c22ux2=2ut2,u(0,t) =0,u(1,t) =0,u(x,0) ={x if 0<x<1/21x if 1/2<x<1}c ^ { 2 } \frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } = \frac { \partial ^ { 2 } u } { \partial t ^ { 2 } } , u ( 0 , t ) = 0 , u ( 1 , t ) = 0 , u ( x , 0 ) = \left\{ \begin{array} { c c c } x & \text { if } & 0 < x < 1 / 2 \\1 - x & \text { if } & 1 / 2 < x < 1\end{array} \right\} , ut(x,0) =g(x) u _ { t } ( x , 0 ) = g ( x ) . Replace 2ux2\frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } with a central difference approximation with h=1/2h = 1 / 2 and 2ux2\frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } with a central difference approximation with k=1/2k = 1 / 2 . The resulting equation is


A) c2[u(x+h,t) 2u(x,t) +u(xh,t) ]/h2=(u(x,t+k) u(x,t) ) /k2c ^ { 2 } [ u ( x + h , t ) - 2 u ( x , t ) + u ( x - h , t ) ] / h ^ { 2 } = ( u ( x , t + k ) - u ( x , t ) ) / k ^ { 2 }
B) c2[u(x+h,t) 2u(x,t) +u(xh,t) ]/h2=(u(x,t+k) +u(x,t) ) /kc ^ { 2 } [ u ( x + h , t ) - 2 u ( x , t ) + u ( x - h , t ) ] / h ^ { 2 } = ( u ( x , t + k ) + u ( x , t ) ) / k
C) c2[u(x+h,t) 2u(x,t) +u(xh,t) ]/h2=(u(x,t+k) u(x,t) ) /kc ^ { 2 } [ u ( x + h , t ) - 2 u ( x , t ) + u ( x - h , t ) ] / h ^ { 2 } = ( u ( x , t + k ) - u ( x , t ) ) / k
D) c2[u(x+h,t) 2u(x,t) +u(xh,t) ]/h2=(u(x,t+k) u(x,t) +u(x,tk) ) /k2c ^ { 2 } [ u ( x + h , t ) - 2 u ( x , t ) + u ( x - h , t ) ] / h ^ { 2 } = ( u ( x , t + k ) - u ( x , t ) + u ( x , t - k ) ) / k ^ { 2 }
E) c2[u(x+h,t) 2u(x,t) +u(xh,t) ]/h2=(u(x,t+k) 2u(x,t) +u(x,tk) ) /k2c ^ { 2 } [ u ( x + h , t ) - 2 u ( x , t ) + u ( x - h , t ) ] / h ^ { 2 } = ( u ( x , t + k ) - 2 u ( x , t ) + u ( x , t - k ) ) / k ^ { 2 }

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