Solved

The Solution of the System in the Previous Problem Is x=2e−3t−e2t,y=2e−3t−2e2tx = 2 e ^ { - 3 t } - e ^ { 2 t } , y = 2 e ^ { - 3 t } - 2 e ^ { 2 t }

Question 12

Multiple Choice

The solution of the system in the previous problem is


A) x=2e−3t−e2t,y=2e−3t−2e2tx = 2 e ^ { - 3 t } - e ^ { 2 t } , y = 2 e ^ { - 3 t } - 2 e ^ { 2 t }
B) x=2e3t−e−2t,y=2e3t−2e−2tx = 2 e ^ { 3 t } - e ^ { - 2 t } , y = 2 e ^ { 3 t } - 2 e ^ { - 2 t }
C) x=2e3t−e2t,y=2e3t−2e2tx = 2 e ^ { 3 t } - e ^ { 2 t } , y = 2 e ^ { 3 t } - 2 e ^ { 2 t }
D) x=2e−3t−e−2t,y=2e−3t−2e−2tx = 2 e ^ { - 3 t } - e ^ { - 2 t } , y = 2 e ^ { - 3 t } - 2 e ^ { - 2 t }
E) x=2e3t+e2t,y=2e3t+2e2tx = 2 e ^ { 3 t } + e ^ { 2 t } , y = 2 e ^ { 3 t } + 2 e ^ { 2 t }

Correct Answer:

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