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The Solution of the Differential Equation of the Previous Problem θ=ce2t\theta = c e ^ { 2 t }

Question 5

Multiple Choice

The solution of the differential equation of the previous problem is


A) θ=ce2t\theta = c e ^ { 2 t }
B) θ=ce2t\theta = c e ^ { - 2 t }
C) θ=cet/2\theta = c e ^ { - t / 2 }
D) θ=c1cos(2t) +c2sin(2t) \theta = c _ { 1 } \cos ( 2 t ) + c _ { 2 } \sin ( 2 t )
E) θ=c1cos(2t) +c2sin(2t) \theta = c _ { 1 } \cos ( \sqrt { 2 } t ) + c _ { 2 } \sin ( \sqrt { 2 } t )

Correct Answer:

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