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  2. Topic
    Mathematics
  3. Study Set
    Calculus Early Transcendentals
  4. Exam
    Exam 1: Functions and Limits
  5. Question
    Find the Solutions of the Equation\(\csc (2 \theta)=1\) In\([0,2 \pi)\)
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Find the Solutions of the Equation csc⁡(2θ)=1\csc (2 \theta)=1csc(2θ)=1 In [0,2π)[0,2 \pi)[0,2π)

Question 16

Question 16

Short Answer

Find the solutions of the equation csc⁡(2θ)=1\csc (2 \theta)=1csc(2θ)=1 in [0,2π)[0,2 \pi)[0,2π) .

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