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Use the Figure to Answer the Question θ\theta )- ½ G (2

Question 11

Multiple Choice

Use the figure to answer the question.
The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is Vo at an angle  Use the figure to answer the question. The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is V<sub>o</sub> at an angle   to the horizon. The vertical dashed lines represent equal time interval,     -The vertical velocity at point b is: Note: (g = 9.81 m/s<sup>2</sup>)  A) 0 B) V<sub>o</sub> cos ( \theta ) - ½ g (2 \Delta t) <sup>2</sup> C) V<sub>o</sub> sin ( \theta ) - ½ g (2 \Delta t) <sup>2</sup> D) V<sub>o</sub> sin ( \theta ) + ½ g (2 \Delta t) <sup>2</sup> E) V<sub>o</sub> cos ( \theta ) + ½ g (2 \Delta t) <sup>2</sup> to the horizon. The vertical dashed lines represent equal time interval,  Use the figure to answer the question. The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is V<sub>o</sub> at an angle   to the horizon. The vertical dashed lines represent equal time interval,     -The vertical velocity at point b is: Note: (g = 9.81 m/s<sup>2</sup>)  A) 0 B) V<sub>o</sub> cos ( \theta ) - ½ g (2 \Delta t) <sup>2</sup> C) V<sub>o</sub> sin ( \theta ) - ½ g (2 \Delta t) <sup>2</sup> D) V<sub>o</sub> sin ( \theta ) + ½ g (2 \Delta t) <sup>2</sup> E) V<sub>o</sub> cos ( \theta ) + ½ g (2 \Delta t) <sup>2</sup>
 Use the figure to answer the question. The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is V<sub>o</sub> at an angle   to the horizon. The vertical dashed lines represent equal time interval,     -The vertical velocity at point b is: Note: (g = 9.81 m/s<sup>2</sup>)  A) 0 B) V<sub>o</sub> cos ( \theta ) - ½ g (2 \Delta t) <sup>2</sup> C) V<sub>o</sub> sin ( \theta ) - ½ g (2 \Delta t) <sup>2</sup> D) V<sub>o</sub> sin ( \theta ) + ½ g (2 \Delta t) <sup>2</sup> E) V<sub>o</sub> cos ( \theta ) + ½ g (2 \Delta t) <sup>2</sup>
-The vertical velocity at point b is: Note: (g = 9.81 m/s2)


A) 0
B) Vo cos ( θ\theta ) - ½ g (2 Δ\Delta t) 2
C) Vo sin ( θ\theta ) - ½ g (2 Δ\Delta t) 2
D) Vo sin ( θ\theta ) + ½ g (2 Δ\Delta t) 2
E) Vo cos ( θ\theta ) + ½ g (2 Δ\Delta t) 2

Correct Answer:

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