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Starting with the Expression for Work , One Can

Question 56

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Starting with the expression for work Starting with the expression for work , one can change the look of the expression without changing what it represents by dividing the force F by the area it is applied over and multiplying the differential distance dx by that same area. Force divided by area is a pressure (P) , and area times the differential distance is a differential volume. Hence one can also describe work as . A gas at constant temperature will change its pressure inversely to changes in volume, . If a sample of gas has a pressure of 1 atmosphere when its volume is 1 L, how much work does it do when it expands from 1 L to 3 L? A) B) C) D) , one can change the look of the expression without changing what it represents by dividing the force F by the area it is applied over and multiplying the differential distance dx by that same area. Force divided by area is a pressure (P) , and area times the differential distance is a differential volume. Hence one can also describe work as Starting with the expression for work , one can change the look of the expression without changing what it represents by dividing the force F by the area it is applied over and multiplying the differential distance dx by that same area. Force divided by area is a pressure (P) , and area times the differential distance is a differential volume. Hence one can also describe work as . A gas at constant temperature will change its pressure inversely to changes in volume, . If a sample of gas has a pressure of 1 atmosphere when its volume is 1 L, how much work does it do when it expands from 1 L to 3 L? A) B) C) D) . A gas at constant temperature will change its pressure inversely to changes in volume, Starting with the expression for work , one can change the look of the expression without changing what it represents by dividing the force F by the area it is applied over and multiplying the differential distance dx by that same area. Force divided by area is a pressure (P) , and area times the differential distance is a differential volume. Hence one can also describe work as . A gas at constant temperature will change its pressure inversely to changes in volume, . If a sample of gas has a pressure of 1 atmosphere when its volume is 1 L, how much work does it do when it expands from 1 L to 3 L? A) B) C) D) . If a sample of gas has a pressure of 1 atmosphere when its volume is 1 L, how much work does it do when it expands from 1 L to 3 L?


A) Starting with the expression for work , one can change the look of the expression without changing what it represents by dividing the force F by the area it is applied over and multiplying the differential distance dx by that same area. Force divided by area is a pressure (P) , and area times the differential distance is a differential volume. Hence one can also describe work as . A gas at constant temperature will change its pressure inversely to changes in volume, . If a sample of gas has a pressure of 1 atmosphere when its volume is 1 L, how much work does it do when it expands from 1 L to 3 L? A) B) C) D)
B) Starting with the expression for work , one can change the look of the expression without changing what it represents by dividing the force F by the area it is applied over and multiplying the differential distance dx by that same area. Force divided by area is a pressure (P) , and area times the differential distance is a differential volume. Hence one can also describe work as . A gas at constant temperature will change its pressure inversely to changes in volume, . If a sample of gas has a pressure of 1 atmosphere when its volume is 1 L, how much work does it do when it expands from 1 L to 3 L? A) B) C) D)
C) Starting with the expression for work , one can change the look of the expression without changing what it represents by dividing the force F by the area it is applied over and multiplying the differential distance dx by that same area. Force divided by area is a pressure (P) , and area times the differential distance is a differential volume. Hence one can also describe work as . A gas at constant temperature will change its pressure inversely to changes in volume, . If a sample of gas has a pressure of 1 atmosphere when its volume is 1 L, how much work does it do when it expands from 1 L to 3 L? A) B) C) D)
D) Starting with the expression for work , one can change the look of the expression without changing what it represents by dividing the force F by the area it is applied over and multiplying the differential distance dx by that same area. Force divided by area is a pressure (P) , and area times the differential distance is a differential volume. Hence one can also describe work as . A gas at constant temperature will change its pressure inversely to changes in volume, . If a sample of gas has a pressure of 1 atmosphere when its volume is 1 L, how much work does it do when it expands from 1 L to 3 L? A) B) C) D)

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