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Find a Unit Vector Perpendicular to the Plane X - (23,23,13)\left( - \frac { 2 } { 3 } , - \frac { 2 } { 3 } , \frac { 1 } { 3 } \right)

Question 118

Multiple Choice

Find a unit vector perpendicular to the plane x - 2y - 2z = 10.


A) (23,23,13) \left( - \frac { 2 } { 3 } , - \frac { 2 } { 3 } , \frac { 1 } { 3 } \right)
B) (13,23,23) \left( - \frac { 1 } { 3 } , \frac { 2 } { 3 } , \frac { 2 } { 3 } \right)
C) 13,23,23}\left\langle \frac { 1 } { 3 } , \frac { 2 } { 3 } , \frac { 2 } { 3 } \right\}
D) 23,23,13}\left\langle \frac { 2 } { 3 } , \frac { 2 } { 3 } , \frac { 1 } { 3 } \right\}
E) (12,12,0) \left( \frac { 1 } { \sqrt { 2 } } , \frac { 1 } { \sqrt { 2 } } , 0 \right)
F) (12,0,12) \left( \frac { 1 } { \sqrt { 2 } } , 0 , \frac { 1 } { \sqrt { 2 } } \right)
G) (0,12,12) \left( 0 , \frac { 1 } { \sqrt { 2 } } , \frac { 1 } { \sqrt { 2 } } \right)
H) {1,0,0}\{ - 1,0,0 \}

Correct Answer:

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