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Given ∫04f(x)dx=−5 and ∫06f(x)dx=3\int _ { 0 } ^ { 4 } f ( x ) d x = - 5 \text { and } \int _ { 0 } ^ { 6 } f ( x ) d x = 3

Question 236

Short Answer

Given ∫04f(x)dx=−5 and ∫06f(x)dx=3\int _ { 0 } ^ { 4 } f ( x ) d x = - 5 \text { and } \int _ { 0 } ^ { 6 } f ( x ) d x = 3 use the properties of definite integrals to find ∫64f(x)dx.\int _ { 6 } ^ { 4 } f ( x ) d x .

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