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Find dydx\frac { d y } { d x } (A) y=ln4x7x2+2xy = \ln \sqrt { \frac { 4 x - 7 } { x ^ { 2 } + 2 x } }

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Find dydx\frac { d y } { d x } .(a) y=ln4x7x2+2xy = \ln \sqrt { \frac { 4 x - 7 } { x ^ { 2 } + 2 x } } (b) y=(ln(secx))4y = ( \ln ( \sec x ) ) ^ { 4 } (c) y=(1+1x)2xy = \left( 1 + \frac { 1 } { x } \right) ^ { 2 x }

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