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Let p(t)=20,0001+1999e0.1tp ( t ) = \frac { 20,000 } { 1 + 1999 e ^ { - 0.1 t } }

Question 191

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Let p(t)=20,0001+1999e0.1tp ( t ) = \frac { 20,000 } { 1 + 1999 e ^ { - 0.1 t } } be the population of a bacteria colony at time t hours. Find the growth rate of the bacteria after 10 hours.

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