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What Point on the Surface 1x+1y+1z=1\frac { 1 } { x } + \frac { 1 } { y } + \frac { 1 } { z } = 1

Question 153

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What point on the surface 1x+1y+1z=1\frac { 1 } { x } + \frac { 1 } { y } + \frac { 1 } { z } = 1 , x>0x > 0 , y>0y > 0 , z>0z > 0 is closest to the origin?

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