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    Chemical Principles Study Set 4
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    Exam 15: Chemical Kinetics
  5. Question
    For the Reaction CH<sub>3</sub>CHCH<sub>2</sub>(g) + HCl(g) → CH<sub>3</sub>CHClCH<sub>3</sub>(g)
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For the Reaction CH3CHCH2(g) + HCl(g) → CH3CHClCH3(g)

Question 56

Question 56

Short Answer

For the reaction
CH3CHCH2(g) + HCl(g) → CH3CHClCH3(g)
a possible mechanism is For the reaction CH<sub>3</sub>CHCH<sub>2</sub>(g) + HCl(g) → CH<sub>3</sub>CHClCH<sub>3</sub>(g) a possible mechanism is    Fast equilibrium        Fast equilibrium Complex + (HCl)<sub>2</sub>    CH<sub>3</sub>CHClCH<sub>3</sub> + 2HCl Slow Derive the rate law for this reaction using this mechanism.
Fast equilibrium For the reaction CH<sub>3</sub>CHCH<sub>2</sub>(g) + HCl(g) → CH<sub>3</sub>CHClCH<sub>3</sub>(g) a possible mechanism is    Fast equilibrium        Fast equilibrium Complex + (HCl)<sub>2</sub>    CH<sub>3</sub>CHClCH<sub>3</sub> + 2HCl Slow Derive the rate law for this reaction using this mechanism.
For the reaction CH<sub>3</sub>CHCH<sub>2</sub>(g) + HCl(g) → CH<sub>3</sub>CHClCH<sub>3</sub>(g) a possible mechanism is    Fast equilibrium        Fast equilibrium Complex + (HCl)<sub>2</sub>    CH<sub>3</sub>CHClCH<sub>3</sub> + 2HCl Slow Derive the rate law for this reaction using this mechanism.
Fast equilibrium
Complex + (HCl)2 For the reaction CH<sub>3</sub>CHCH<sub>2</sub>(g) + HCl(g) → CH<sub>3</sub>CHClCH<sub>3</sub>(g) a possible mechanism is    Fast equilibrium        Fast equilibrium Complex + (HCl)<sub>2</sub>    CH<sub>3</sub>CHClCH<sub>3</sub> + 2HCl Slow Derive the rate law for this reaction using this mechanism.
CH3CHClCH3 + 2HCl
Slow
Derive the rate law for this reaction using this mechanism.

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