Solved

A 500-ML Sample of 2

Question 57

Multiple Choice

A 50.0-mL sample of 2.0 × 10-4 M CuNO3 is added to 50.0 mL of 4.0 M NaCN. Cu+ reacts with CN- to form the complex ion Cu(CN) 32-: A 50.0-mL sample of 2.0 × 10<sup>-4</sup> M CuNO<sub>3</sub> is added to 50.0 mL of 4.0 M NaCN. Cu<sup>+</sup> reacts with CN<sup>-</sup> to form the complex ion Cu(CN) <sub>3</sub><sup>2-</sup>:   What is the concentration of CN<sup>-</sup> at equilibrium? A)  6.0 × 10<sup>-4</sup> M B)  1.0 M C)  4.0 M D)  2.0 M E)  none of these What is the concentration of CN- at equilibrium?


A) 6.0 × 10-4 M
B) 1.0 M
C) 4.0 M
D) 2.0 M
E) none of these

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions