Multiple Choice
A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 × 10-3 M CuNO3. Cu(I) forms complex ions with cyanide as follows: ![A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 × 10<sup>-3</sup> M CuNO<sub>3</sub>. Cu(I) forms complex ions with cyanide as follows: Calculate the following concentrations at equilibrium: -[Cu(CN) <sub>3</sub><sup>2-</sup>] A) 3.33 M B) 1.67 M C) 2.0 × 10<sup>-3</sup> M D) 1.0 × 10<sup>-3</sup> M E) none of these](https://d2lvgg3v3hfg70.cloudfront.net/TB6422/11eaaf91_9e28_6ed1_892c_81ba02cfc46a_TB6422_00_TB6422_00_TB6422_00.jpg)
Calculate the following concentrations at equilibrium:
-[Cu(CN) 32-]
A) 3.33 M
B) 1.67 M
C) 2.0 × 10-3 M
D) 1.0 × 10-3 M
E) none of these
Correct Answer:
Verified
Correct Answer:
Verified
Q82: Calculate the molar solubility of BaCO<sub>3</sub> (K<sub>sp</sub>
Q83: Derive the equation describing the relationship between
Q84: An indicator HIn has K<sub>a</sub> = 1
Q85: Which of the following statements is/are true
Q86: Calculate [H<sup>+</sup>] in a solution that is
Q88: Consider a solution made by mixing 500.0
Q89: 12.4 mL of 0.25 M HCl is
Q90: The pH at the equivalence point of
Q91: A 10-mL sample of tartaric acid is
Q92: For the compound MX, K<sub>sp</sub> is 2.00