Multiple Choice
A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 × 10-3 M CuNO3. Cu(I) forms complex ions with cyanide as follows: ![A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 × 10<sup>-3</sup> M CuNO<sub>3</sub>. Cu(I) forms complex ions with cyanide as follows: Calculate the following concentrations at equilibrium: -[Cu(CN) <sub>2</sub><sup>-</sup>] A) 1.0 × 10<sup>-3</sup> M B) 4.0 × 10<sup>-12</sup> M C) 2.0 × 10<sup>-7</sup> M D) 2.0 × 10<sup>-3</sup> M E) none of these](https://d2lvgg3v3hfg70.cloudfront.net/TB6422/11eaaf91_9e28_6ed1_892c_81ba02cfc46a_TB6422_00_TB6422_00_TB6422_00.jpg)
Calculate the following concentrations at equilibrium:
-[Cu(CN) 2-]
A) 1.0 × 10-3 M
B) 4.0 × 10-12 M
C) 2.0 × 10-7 M
D) 2.0 × 10-3 M
E) none of these
Correct Answer:
Verified
Correct Answer:
Verified
Q27: A solution containing 10. mmol of CO<sub>3</sub><sup>2-</sup>
Q28: Equal volumes of 0.1 M HCl and
Q29: For carbonic acid (H<sub>2</sub>CO<sub>3</sub>), K<sub>a1</sub> = 4.30
Q30: A solution is formed by mixing 50.0
Q31: A 200.0-mL sample of the weak acid
Q33: In the titration of 250.0 mL of
Q34: The overall K<sub>f</sub> for the complex ion
Q35: How many moles of CaF<sub>2</sub> will dissolve
Q36: The concentration of Mg<sup>2+</sup> in seawater is
Q37: The solubility of Fe(OH)<sub>2</sub> in water is