Multiple Choice
A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 × 10-3 M CuNO3. Cu(I) forms complex ions with cyanide as follows: ![A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 × 10<sup>-3</sup> M CuNO<sub>3</sub>. Cu(I) forms complex ions with cyanide as follows: Calculate the following concentrations at equilibrium: -[Cu<sup>+</sup>] A) 2.0 × 10<sup>-13</sup> M B) 8.0 × 10<sup>-15</sup> M C) 1.6 × 10<sup>-13</sup> M D) 4.0 × 10<sup>-13</sup> M E) none of these](https://d2lvgg3v3hfg70.cloudfront.net/TB6422/11eaaf91_9e28_6ed1_892c_81ba02cfc46a_TB6422_00_TB6422_00_TB6422_00.jpg)
Calculate the following concentrations at equilibrium:
-[Cu+]
A) 2.0 × 10-13 M
B) 8.0 × 10-15 M
C) 1.6 × 10-13 M
D) 4.0 × 10-13 M
E) none of these
Correct Answer:
Verified
Correct Answer:
Verified
Q25: What quantity of NaOH(s) must be added
Q26: Methyl orange is an indicator with a
Q27: A solution containing 10. mmol of CO<sub>3</sub><sup>2-</sup>
Q28: Equal volumes of 0.1 M HCl and
Q29: For carbonic acid (H<sub>2</sub>CO<sub>3</sub>), K<sub>a1</sub> = 4.30
Q31: A 200.0-mL sample of the weak acid
Q32: A solution is formed by mixing 50.0
Q33: In the titration of 250.0 mL of
Q34: The overall K<sub>f</sub> for the complex ion
Q35: How many moles of CaF<sub>2</sub> will dissolve