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Fifteen μ\mu G of an Enzyme of Mr 30,000 Working at Vmax

Question 64

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Fifteen μ\mu g of an enzyme of Mr 30,000 working at Vmax catalyzes the conversion of 60 μ\mu mol of substrate into product in 3 min. What is the enzyme's turnover number?

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Answered by ExamLex AI

The turnover number, also known as k_cat...

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