Multiple Choice
What is the mass of iron(III) bromide (295.55 g/mol) that yields 0.188 g of silver bromide (187.77 g/mol) precipitate? __FeBr3(s) + __AgNO₃(aq) → __AgBr(s) + __Fe(NO₃) 3(aq)
A) 0.0986 g
B) 0.148 g
C) 0.296 g
D) 0.592 g
E) 0.888 g
Correct Answer:
Verified
Correct Answer:
Verified
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