Given This Frequency Distribution, the Random Number 0 A) 0
B) 1

Multiple Choice

Given this frequency distribution, the random number 0.9015 would be interpreted as a demand of:
$$\begin{array} { | c | c | } \hline \text { Demand } & \text { Frequency } \\\hline 0 & 38 \\\hline 1 & 22 \\\hline 2 & 22 \\\hline 3 & 18 \\\hline\end{array}$$

A) 0.
B) 1.
C) 2.
D) 3.
E) 1 or 2.