Solved

Solve the Linear Programming Problem by the Method of Corners

Question 72

Multiple Choice

Solve the linear programming problem by the method of corners. Find the maximum and minimum of Solve the linear programming problem by the method of corners. Find the maximum and minimum of   subject to           A)  Max: x = 0; y = 5; P = 131 Min: x = 5; y = 15; P = 42 B)  Max: x = 5; y = 15; P = 131 Min: x = 0; y = 5; P = 42 C)  Max: x = 5; y = 15; P = 130 Min: x = 0; y = 5; P = 40 D)  Max: x = 0; y = 5; P = 130 Min: x = 5; y = 15; P = 40 subject to Solve the linear programming problem by the method of corners. Find the maximum and minimum of   subject to           A)  Max: x = 0; y = 5; P = 131 Min: x = 5; y = 15; P = 42 B)  Max: x = 5; y = 15; P = 131 Min: x = 0; y = 5; P = 42 C)  Max: x = 5; y = 15; P = 130 Min: x = 0; y = 5; P = 40 D)  Max: x = 0; y = 5; P = 130 Min: x = 5; y = 15; P = 40 Solve the linear programming problem by the method of corners. Find the maximum and minimum of   subject to           A)  Max: x = 0; y = 5; P = 131 Min: x = 5; y = 15; P = 42 B)  Max: x = 5; y = 15; P = 131 Min: x = 0; y = 5; P = 42 C)  Max: x = 5; y = 15; P = 130 Min: x = 0; y = 5; P = 40 D)  Max: x = 0; y = 5; P = 130 Min: x = 5; y = 15; P = 40 Solve the linear programming problem by the method of corners. Find the maximum and minimum of   subject to           A)  Max: x = 0; y = 5; P = 131 Min: x = 5; y = 15; P = 42 B)  Max: x = 5; y = 15; P = 131 Min: x = 0; y = 5; P = 42 C)  Max: x = 5; y = 15; P = 130 Min: x = 0; y = 5; P = 40 D)  Max: x = 0; y = 5; P = 130 Min: x = 5; y = 15; P = 40 Solve the linear programming problem by the method of corners. Find the maximum and minimum of   subject to           A)  Max: x = 0; y = 5; P = 131 Min: x = 5; y = 15; P = 42 B)  Max: x = 5; y = 15; P = 131 Min: x = 0; y = 5; P = 42 C)  Max: x = 5; y = 15; P = 130 Min: x = 0; y = 5; P = 40 D)  Max: x = 0; y = 5; P = 130 Min: x = 5; y = 15; P = 40 Solve the linear programming problem by the method of corners. Find the maximum and minimum of   subject to           A)  Max: x = 0; y = 5; P = 131 Min: x = 5; y = 15; P = 42 B)  Max: x = 5; y = 15; P = 131 Min: x = 0; y = 5; P = 42 C)  Max: x = 5; y = 15; P = 130 Min: x = 0; y = 5; P = 40 D)  Max: x = 0; y = 5; P = 130 Min: x = 5; y = 15; P = 40


A) Max: x = 0; y = 5; P = 131
Min: x = 5; y = 15; P = 42
B) Max: x = 5; y = 15; P = 131
Min: x = 0; y = 5; P = 42
C) Max: x = 5; y = 15; P = 130
Min: x = 0; y = 5; P = 40
D) Max: x = 0; y = 5; P = 130
Min: x = 5; y = 15; P = 40

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions