Exam 20: Entropy and the Second Law of Thermodynamics

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On a warm day a pool of water transfers energy to the air as heat and freezes.This is a direct violation of:

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A force of 5 N stretches an elastic band at room temperature.The rate at which its entropy changes as it stretches is about:

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An ideal gas is to taken reversibly from state i, at temperature T1, to other states labeled I, II, III, IV and V on the p-V diagram below.All are at the same temperature T2. Rank the five processes according to the change in entropy of the gas, least to greatest. An ideal gas is to taken reversibly from state i, at temperature T<sub>1</sub>, to other states labeled I, II, III, IV and V on the p-V diagram below.All are at the same temperature T<sub>2.</sub> Rank the five processes according to the change in entropy of the gas, least to greatest.

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A Carnot heat engine runs between a cold reservoir at temperature TL and a hot reservoir at temperature TH.You want to increase its efficiency.Of the following, which change results in the greatest increase in efficiency? The value of Δ\Delta T is the same for all changes.

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Possible units of entropy are:

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A hot object and a cold object are placed in thermal contact and the combination is isolated.They transfer energy until they reach a common temperature.The change Δ\Delta Sh in the entropy of the hot object, the change Δ\Delta Sc in the entropy of the cold object, and the change Δ\Delta Stotal in the entropy of the combination are:

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For a system of molecules,

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An ideal gas, consisting of n moles, undergoes a reversible isothermal process during which the volume changes from Vi to Vf.The change in entropy of the thermal reservoir in contact with the gas is given by:

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A heat engine in each cycle absorbs energy from a reservoir as heat and does an equivalent amount of work, with no other changes.This engine violates:

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An inventor claims to have a heat engine that has efficiency of 40% when it operates between a high temperature reservoir of 150 °\degree C and a low temperature reservoir of 30 °\degree C.This engine:

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In a reversible process the system:

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A heat engine in each cycle absorbs energy of magnitude \vert QH \vert as heat from a high temperature reservoir, does work of magnitude F \vert W \vert , and then absorbs energy of magnitude \vert QL \vert as heat from a low temperature reservoir.If \vert W \vert = \vert QH \vert + \vert QL \vert this engine violates:

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For all irreversible processes involving a system and its environment:

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According to the second law of thermodynamics:

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Let k be the Boltzmann constant.If the configuration of the molecules in a gas changes so that the multiplicity is reduced to one-third its previous value, the entropy of the gas changes by:

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Which of the following is NOT a state variable?

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A Carnot cycle heat engine operates between 400 K and 500 K.Its efficiency is:

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Consider all possible isothermal contractions of an ideal gas.The entropy of the gas:

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A Carnot refrigerator runs between a cold reservoir at temperature TL and a hot reservoir at temperature TH.You want to increase its coefficient of performance.Of the following, which change results in the greatest increase in the coefficient? The value of Δ\Delta T is the same for all changes.

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The difference in entropy Δ\Delta S = SB - SA for two states A and B of a system can computed as the integral \int dQ/T provided:

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