Exam 4: Introduction to Probability

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The sample space refers to

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Three applications for admission to a local university are checked, and it is determined whether each applicant is male or female.The number of sample points in this experiment is

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Each customer entering a department store will either buy or not buy some merchandise.An experiment consists of following 3 customers and determining whether or not they purchase any merchandise.The number of sample points in this experiment is

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If X and Y are mutually exclusive events with P(A) = 0.295, P(B) = 0.32, then P(A | B) =

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From nine cards numbered 1 through 9, two cards are drawn.Consider the selection and classification of the cards as odd or even as an experiment.How many sample points are there for this experiment?

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Of five letters (A, B, C, D, and E), two letters are to be selected at random.How many possible are possible?

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A lottery is conducted using three urns.Each urn contains chips numbered from 0 to 9.One chip is selected at random from each urn.The total number of sample points in the sample space is

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If P(A) = 0.38, P(B) = 0.83, and P(A ) B) = 0.24; then P(A * B) =

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The range of probability is

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Assuming that each of the 52 cards in an ordinary deck has a probability of 1/52 of being drawn, what is the probability of drawing a black ace?

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​A list of all possible outcomes of an experiment is called the

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If A and B are independent events with P(A) = 0.4 and P(B) = 0.6, then P(A ∩ B) =

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If P(A) = 0.62, P(B) = 0.56, and P(A * B) = 0.70, then P(B | A) =

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The addition law is potentially helpful when we are interested in computing the probability of

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The intersection of two mutually exclusive events

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​The probability of an event is

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An experiment consists of three steps.There are four possible results on the first step, three possible results on the second step, and two possible results on the third step.The total number of experimental outcomes is

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A graphical method of representing the sample points of an experiment is a

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If P(A) = 0.50, P(B) = 0.40 and P(A ∪ B) = 0.88, then P(B |A) =

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If A and B are independent events with P(A) = 0.4 and P(B) = 0.25, then P(A ∪ B) =

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