Question 1

An experiment consists of four outcomes with P(E1) = 0.2, P(E2) = 0.3, and P(E3) = 0.4.The probability of outcome E4 is

Accepted Answer

A)  0.500. 
B)  0.024. 
C)  0.100. 
D)  0.900. 
A)  0.500. 
B)  0.024. 
C)  0.100. 
D)  0.900.

Question 2

In the set of all past due accounts, let the event A mean the account is between 31 and 60 days past due and the event B mean the account is that of a new customer.The union of A and B is​

Accepted Answer

A)  ​all new customers. 
B)  ​all accounts fewer than 31 or more than 60 days past due. 
C)  ​all accounts from new customers and all accounts that are from 31 to 60 days past due. 
D)  ​all new customers whose accounts are between 31 and 60 days past due. 
A)  ​all new customers. 
B)  ​all accounts fewer than 31 or more than 60 days past due. 
C)  ​all accounts from new customers and all accounts that are from 31 to 60 days past due. 
D)  ​all new customers whose accounts are between 31 and 60 days past due.

Question 3

​Posterior probabilities are computed using

Accepted Answer

A)  ​relative frequency. 
B)  ​Chebyshev's theorem. 
C)  ​the empirical rule. 
D)  ​Bayes' theorem. 
A)  ​relative frequency. 
B)  ​Chebyshev's theorem. 
C)  ​the empirical rule. 
D)  ​Bayes' theorem.

Question 4

The complement of P(A | B) is​

Accepted Answer

Question 5

The set of all possible outcomes of an experiment is

Accepted Answer

A)  a sample point. 
B)  an event. 
C)  the population. 
D)  the sample space. 
A)  a sample point. 
B)  an event. 
C)  the population. 
D)  the sample space.

Question 6

If A and B are independent events with P(A) = 0.5 and P(B) = 0.5, then P(A ∩ B)

Accepted Answer

A)  is 0.00. 
B)  is 1.00. 
C)  is 0.5. 
D)  None of these alternatives is correct. 
A)  is 0.00. 
B)  is 1.00. 
C)  is 0.5. 
D)  None of these alternatives is correct.

Question 7

Events A and B are mutually exclusive with P(C) = 0.3 and P(B) = 0.2.Then, P(Bc) =

Accepted Answer

A)  0.06. 
B)  0.50. 
C)  0.70. 
D)  0.80. 
A)  0.06. 
B)  0.50. 
C)  0.70. 
D)  0.80.

Question 8

​If P(A ∩ B) = 0,

Accepted Answer

A)  ​P(
A)  + P(
B)  = 1. 
B)  ​either P(
A)  = 0 or P(
B)  = 0. 
C)  ​A and B are mutually exclusive events. 
D)  ​A and B are independent events. 
A)  ​P(
A)  + P(
B)  = 1. 
B)  ​either P(
A)  = 0 or P(
B)  = 0. 
C)  ​A and B are mutually exclusive events. 
D)  ​A and B are independent events.

Question 9

Assume your favorite soccer team has 2 games left to finish the season.The outcome of each game can be win, lose or tie.The number of possible outcomes is

Accepted Answer

A)  2. 
B)  4. 
C)  6. 
D)  9. 
A)  2. 
B)  4. 
C)  6. 
D)  9.

Question 10

A perfectly balanced coin is tossed 6 times, and tails appears on all six tosses.Then, on the seventh trial

Accepted Answer

A)  tail can not appear. 
B)  head has a larger chance of appearing than tail. 
C)  tail has a better chance of appearing than head. 
D)  tail has same chance of appearing as the head. 
A)  tail can not appear. 
B)  head has a larger chance of appearing than tail. 
C)  tail has a better chance of appearing than head. 
D)  tail has same chance of appearing as the head.

Question 11

If P(A) = 0.62, P(B) = 0.47, and P(A ∪ B) = 0.88, then P(A ∩ B) =

Accepted Answer

A)  0.2914. 
B)  1.9700. 
C)  0.6700. 
D)  0.2100. 
A)  0.2914. 
B)  1.9700. 
C)  0.6700. 
D)  0.2100.

Question 12

If P(A) = 0.58, P(B) = 0.44, and P(A ∩ B) = 0.25, then P(A ∪ B) =

Accepted Answer

A)  1.02. 
B)  0.77. 
C)  0.11. 
D)  0.39. 
A)  1.02. 
B)  0.77. 
C)  0.11. 
D)  0.39.

Question 13

Assume your favorite soccer team has 3 games left to finish the season.The outcome of each game can be win, lose, or tie.How many possible outcomes exist?

Accepted Answer

A)  7 
B)  27 
C)  36 
D)  64 
A)  7 
B)  27 
C)  36 
D)  64

Question 14

The probability of the occurrence of event A in an experiment is 1/3.If the experiment is performed 2 times and event A did not occur, then on the third trial event A

Accepted Answer

A)  must occur. 
B)  may occur. 
C)  could not occur. 
D)  has a 2/3 probability of occurring. 
A)  must occur. 
B)  may occur. 
C)  could not occur. 
D)  has a 2/3 probability of occurring.

Question 15

The probability of an intersection of two events is computed using the​

Accepted Answer

A)  ​addition law. 
B)  ​subtraction law. 
C)  ​multiplication law. 
D)  ​division law. 
A)  ​addition law. 
B)  ​subtraction law. 
C)  ​multiplication law. 
D)  ​division law.

Question 16

If A and B are independent events with P(A) = 0.05 and P(B) = 0.65, then P(A ⏐ B) =

Accepted Answer

A)  0.05. 
B)  0.0325. 
C)  0.65. 
D)  0.8. 
A)  0.05. 
B)  0.0325. 
C)  0.65. 
D)  0.8.

Question 17

If P(A) = 0.45, P(B) = 0.55, and P(A ∪ B) = 0.78, then P(A | B) =

Accepted Answer

A)  0.00 
B)  0.45 
C)  0.22 
D)  0.40 
A)  0.00 
B)  0.45 
C)  0.22 
D)  0.40

Question 18

A method of assigning probabilities which assumes that the experimental outcomes are equally likely is referred to as the

Accepted Answer

A)  objective method. 
B)  classical method. 
C)  subjective method. 
D)  experimental method. 
A)  objective method. 
B)  classical method. 
C)  subjective method. 
D)  experimental method.

Question 19

In statistical experiments, each time the experiment is repeated

Accepted Answer

A)  the same outcome must occur. 
B)  the same outcome can not occur again. 
C)  a different outcome might occur. 
D)  a different out come must occur. 
A)  the same outcome must occur. 
B)  the same outcome can not occur again. 
C)  a different outcome might occur. 
D)  a different out come must occur.

Question 20

In the set of all past due accounts, let the event A mean the account is between 31 and 60 days past due and the event B mean the account is that of a new customer.The complement of A is​

Accepted Answer

A)  ​all new customers. 
B)  ​all accounts fewer than 31 or more than 60 days past due. 
C)  ​all accounts from new customers and all accounts that are from 31 to 60 days past due. 
D)  ​all new customers whose accounts are between 31 and 60 days past due. 
A)  ​all new customers. 
B)  ​all accounts fewer than 31 or more than 60 days past due. 
C)  ​all accounts from new customers and all accounts that are from 31 to 60 days past due. 
D)  ​all new customers whose accounts are between 31 and 60 days past due.

An experiment consists of four outcomes with P(E₁) = 0.2, P(E₂) = 0.3, and P(E₃) = 0.4.The probability of outcome E₄ is

In the set of all past due accounts, let the event A mean the account is between 31 and 60 days past due and the event B mean the account is that of a new customer.The union of A and B is

Posterior probabilities are computed using

The complement of P(A | B) is

The set of all possible outcomes of an experiment is

If A and B are independent events with P(A) = 0.5 and P(B) = 0.5, then P(A ∩ B)

Events A and B are mutually exclusive with P(C) = 0.3 and P(B) = 0.2.Then, P(B^c) =

If P(A ∩ B) = 0,

Assume your favorite soccer team has 2 games left to finish the season.The outcome of each game can be win, lose or tie.The number of possible outcomes is

A perfectly balanced coin is tossed 6 times, and tails appears on all six tosses.Then, on the seventh trial

If P(A) = 0.62, P(B) = 0.47, and P(A ∪ B) = 0.88, then P(A ∩ B) =

If P(A) = 0.58, P(B) = 0.44, and P(A ∩ B) = 0.25, then P(A ∪ B) =

Assume your favorite soccer team has 3 games left to finish the season.The outcome of each game can be win, lose, or tie.How many possible outcomes exist?

The probability of the occurrence of event A in an experiment is 1/3.If the experiment is performed 2 times and event A did not occur, then on the third trial event A

The probability of an intersection of two events is computed using the

If A and B are independent events with P(A) = 0.05 and P(B) = 0.65, then P(A ⏐ B) =

If P(A) = 0.45, P(B) = 0.55, and P(A ∪ B) = 0.78, then P(A | B) =

A method of assigning probabilities which assumes that the experimental outcomes are equally likely is referred to as the

In statistical experiments, each time the experiment is repeated

In the set of all past due accounts, let the event A mean the account is between 31 and 60 days past due and the event B mean the account is that of a new customer.The complement of A is

Data and Statistics

Descriptive Statistics: Tabulargraphical

Descriptive Statistics: Numerical

Discrete Probability Distributions

Continuous Probability Distributions

Sampling and Sampling Distributions

Interval Estimation

Hypothesis Tests

Inference About Means and Proportions With Two Populations

Inferences About Population Variances

Comparing Multiple Proportions, Test of Independence and Goodness of Fit

Experimental Design and Analysis of Variance

Simple Linear Regression

Multiple Regression

Filters

Exam 4: Introduction to Probability

An experiment consists of four outcomes with P(E1) = 0.2, P(E2) = 0.3, and P(E3) = 0.4.The probability of outcome E4 is

In the set of all past due accounts, let the event A mean the account is between 31 and 60 days past due and the event B mean the account is that of a new customer.The union of A and B is​

​Posterior probabilities are computed using

The complement of P(A | B) is​

The set of all possible outcomes of an experiment is

If A and B are independent events with P(A) = 0.5 and P(B) = 0.5, then P(A ∩ B)

Events A and B are mutually exclusive with P(C) = 0.3 and P(B) = 0.2.Then, P(Bc) =

​If P(A ∩ B) = 0,

Assume your favorite soccer team has 2 games left to finish the season.The outcome of each game can be win, lose or tie.The number of possible outcomes is

A perfectly balanced coin is tossed 6 times, and tails appears on all six tosses.Then, on the seventh trial

If P(A) = 0.62, P(B) = 0.47, and P(A ∪ B) = 0.88, then P(A ∩ B) =

If P(A) = 0.58, P(B) = 0.44, and P(A ∩ B) = 0.25, then P(A ∪ B) =

Assume your favorite soccer team has 3 games left to finish the season.The outcome of each game can be win, lose, or tie.How many possible outcomes exist?

The probability of the occurrence of event A in an experiment is 1/3.If the experiment is performed 2 times and event A did not occur, then on the third trial event A

The probability of an intersection of two events is computed using the​

If A and B are independent events with P(A) = 0.05 and P(B) = 0.65, then P(A ⏐ B) =

If P(A) = 0.45, P(B) = 0.55, and P(A ∪ B) = 0.78, then P(A | B) =

A method of assigning probabilities which assumes that the experimental outcomes are equally likely is referred to as the

In statistical experiments, each time the experiment is repeated

In the set of all past due accounts, let the event A mean the account is between 31 and 60 days past due and the event B mean the account is that of a new customer.The complement of A is​

Data and Statistics

Descriptive Statistics: Tabulargraphical

Descriptive Statistics: Numerical

Discrete Probability Distributions

Continuous Probability Distributions

Sampling and Sampling Distributions

Interval Estimation

Hypothesis Tests

Inference About Means and Proportions With Two Populations

Inferences About Population Variances

Comparing Multiple Proportions, Test of Independence and Goodness of Fit

Experimental Design and Analysis of Variance

Simple Linear Regression

Multiple Regression

Filters

An experiment consists of four outcomes with P(E₁) = 0.2, P(E₂) = 0.3, and P(E₃) = 0.4.The probability of outcome E₄ is

In the set of all past due accounts, let the event A mean the account is between 31 and 60 days past due and the event B mean the account is that of a new customer.The union of A and B is

Posterior probabilities are computed using

The complement of P(A | B) is

Events A and B are mutually exclusive with P(C) = 0.3 and P(B) = 0.2.Then, P(B^c) =

If P(A ∩ B) = 0,

The probability of an intersection of two events is computed using the

In the set of all past due accounts, let the event A mean the account is between 31 and 60 days past due and the event B mean the account is that of a new customer.The complement of A is