Exam 2: Functions and Graphs

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Evaluate the piecewise function at the given value of the independent variable. - h(x)={x27x+6 if x6x2 if x=6;h(6)h ( x ) = \left\{ \begin{array} { l l } \frac { x ^ { 2 } - 7 } { x + 6 } & \text { if } x \neq - 6 \\ x - 2 & \text { if } x = - 6 \end{array} ; h ( - 6 ) \right.

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D

Based on the graph, find the range of y = f(x). - f(x)={4 if 6x<2x if 2x<8x if 8x13f(x)=\left\{\begin{array}{ll}4 & \text { if }-6 \leq x<-2 \\|x| & \text { if }-2 \leq x<8 \\\sqrt{x} & \text { if } 8 \leq x \leq 13\end{array}\right.  Based on the graph, find the range of y = f(x). - f(x)=\left\{\begin{array}{ll} 4 & \text { if }-6 \leq x<-2 \\ |x| & \text { if }-2 \leq x<8 \\ \sqrt{x} & \text { if } 8 \leq x \leq 13 \end{array}\right.

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Evaluate the function at the given value of the independent variable and simplify. - f(x)=x23;f(x4)f ( x ) = x ^ { 2 } - 3 ; \quad f ( x - 4 )

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Identify the intervals where the function is changing as requested. -Constant Identify the intervals where the function is changing as requested. -Constant

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Graph the given functions on the same rectangular coordinate system. Describe how the graph of g is related to the graph of f. - (x)=x,g(x)=x2(x)=\sqrt{x}, g(x)=\sqrt{x}-2  Graph the given functions on the same rectangular coordinate system. Describe how the graph of g is related to the graph of f. - (x)=\sqrt{x}, g(x)=\sqrt{x}-2

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Graph the given functions on the same rectangular coordinate system. Describe how the graph of g is related to the graph of f. - f(x)=x3,g(x)=x3+2f(x)=x^{3}, g(x)=x^{3}+2  Graph the given functions on the same rectangular coordinate system. Describe how the graph of g is related to the graph of f. - f(x)=x^{3}, g(x)=x^{3}+2

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Graph the given functions on the same rectangular coordinate system. Describe how the graph of g is related to the graph of f. - f(x)=x,g(x)=x4f(x)=|x|, g(x)=|x|-4  Graph the given functions on the same rectangular coordinate system. Describe how the graph of g is related to the graph of f. - f(x)=|x|, g(x)=|x|-4

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Give the domain and range of the relation. -{(10, -3), (12, 3), (-8, -7), (6, -1)}

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Graph the given functions on the same rectangular coordinate system. Describe how the graph of g is related to the graph of f. - (x)=2x,g(x)=2x3(x)=-2 x, g(x)=-2 x-3  Graph the given functions on the same rectangular coordinate system. Describe how the graph of g is related to the graph of f. - (x)=-2 x, g(x)=-2 x-3

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Identify the intercepts -Identify the intercepts -

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Use the vertical line test to determine whether or not the graph is a graph in which y is a function of x. -Use the vertical line test to determine whether or not the graph is a graph in which y is a function of x. -

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Find the slope of the line that goes through the given points. -(2, -3), (-7, 8)

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Use the vertical line test to determine whether or not the graph is a graph in which y is a function of x. -Use the vertical line test to determine whether or not the graph is a graph in which y is a function of x. -

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Use the vertical line test to determine whether or not the graph is a graph in which y is a function of x. -Use the vertical line test to determine whether or not the graph is a graph in which y is a function of x. -

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Based on the graph, find the range of y = f(x). - f(x)={12x if x07 if x=0f(x)=\left\{\begin{array}{ll}-\frac{1}{2} x & \text { if } x \neq 0 \\-7 & \text { if } x=0\end{array}\right.  Based on the graph, find the range of y = f(x). - f(x)=\left\{\begin{array}{ll} -\frac{1}{2} x & \text { if } x \neq 0 \\ -7 & \text { if } x=0 \end{array}\right.

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Use the graph to find the indicated function value. -y = f(x). Find f(3). Use the graph to find the indicated function value. -y = f(x). Find f(3).

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Determine whether the equation defines y as a function of x. - x+y3=27x + y ^ { 3 } = 27

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Use the graph of the given function to find any relative maxima and relative minima. - f(x)=x312x+2f(x)=x^{3}-12 x+2  Use the graph of the given function to find any relative maxima and relative minima. - f(x)=x^{3}-12 x+2

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Write the word or phrase that best completes each statement or answers the question. -The wind chill factor represents the equivalent air temperature at a standard wind speed that would produce W(t)={t if 0v<1.7933(10.45+10vv)(33t)22.04 if 1.79v<20331.5958(33t) if v20W ( t ) = \left\{ \begin{array} { l l } t & \text { if } 0 \leq v < 1.79 \\33 - \frac { ( 10.45 + 10 \sqrt { v } - v ) ( 33 - t ) } { 22.04 } & \text { if } 1.79 \leq v < 20 \\33 - 1.5958 ( 33 - t ) & \text { if } v \geq 20\end{array} \right. where v represents the wind speed (in meters per second)and t represents the air temperature (°C). Compute the wind chill for an air temperature of 15°C and a wind speed of 12 meters per second. (Round the answer to one decimal place.)

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Evaluate the piecewise function at the given value of the independent variable. - (x)={x+1 if x<13 if x1(x)=\left\{\begin{array}{ll}x+1 & \text { if } x<1 \\3 & \text { if } x \geq 1\end{array}\right.  Evaluate the piecewise function at the given value of the independent variable. - (x)=\left\{\begin{array}{ll} x+1 & \text { if } x<1 \\ 3 & \text { if } x \geq 1 \end{array}\right.

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