Exam 2: Functions and Graphs

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Determine whether the given function is even, odd, or neither. - f(x)=5x5+x3f ( x ) = - 5 x ^ { 5 } + x ^ { 3 }

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Determine whether the relation is a function. -{(-7, -8), (-7, -5), (2, 2), (4, -8), (10, 6)}

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Evaluate the piecewise function at the given value of the independent variable. - f(x)={x+3 if x<22x3 if x2f ( x ) = \left\{ \begin{array} { l l } - x + 3 & \text { if } x < 2 \\2 x - 3 & \text { if } x \geq 2\end{array} \right.  Evaluate the piecewise function at the given value of the independent variable. - f ( x ) = \left\{ \begin{array} { l l }  - x + 3 & \text { if } x < 2 \\ 2 x - 3 & \text { if } x \geq 2 \end{array} \right.

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Give the domain and range of the relation. -{(6, 7), (10, -8), (9, 6), (9, 2)}

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