Question 1

Solve.
-$\left| \frac { 1 } { 4 } x + 1 \right| = \left| \frac { 1 } { 2 } x - 1 \right|$

Accepted Answer

A)  $\left\{ 0 , \frac { 8 } { 3 } \right\}$ 
B)   {0,8} 
C)  $\left\{ 0 , \frac { 1 } { 2 } \right\}$ 
D)  $\phi$ 
A)  $\left\{ 0 , \frac { 8 } { 3 } \right\}$ 
B)   {0,8} 
C)  $\left\{ 0 , \frac { 1 } { 2 } \right\}$ 
D)  $\phi$

Question 2

Solve the equation for the specified variable.
-$C = \frac { 5 } { 9 } ( F - 32 ) \text { for } F$

Accepted Answer

A)  $F = \frac { 9 } { 5 } C + 32$ 
B)  $\mathrm { F } = \frac { 9 } { 5 } \mathrm {~F} - 32$ 
C)  $F = \frac { 5 } { 9 } C + 32$ 
D)  $F = \frac { 5 } { 9 } F - 32$ 
A)  $F = \frac { 9 } { 5 } C + 32$ 
B)  $\mathrm { F } = \frac { 9 } { 5 } \mathrm {~F} - 32$ 
C)  $F = \frac { 5 } { 9 } C + 32$ 
D)  $F = \frac { 5 } { 9 } F - 32$

Solve. - $\left| \frac { 1 } { 4 } x + 1 \right| = \left| \frac { 1 } { 2 } x - 1 \right|$

Solve the equation for the specified variable. - $C = \frac { 5 } { 9 } ( F - 32 ) \text { for } F$

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Exam 2: Equations, Inequalities, and Problem Solving

Solve. - ∣14x+1∣=∣12x−1∣\left| \frac { 1 } { 4 } x + 1 \right| = \left| \frac { 1 } { 2 } x - 1 \right|​41​x+1​=​21​x−1​

Solve the equation for the specified variable. - C=59(F−32) for FC = \frac { 5 } { 9 } ( F - 32 ) \text { for } FC=95​(F−32) for F