Exam 6: The Normal Distribution and Other Continuous Distributions
Exam 1: Defining and Collecting Data202 Questions
Exam 2: Organizing and Visualizing256 Questions
Exam 3: Numerical Descriptive Measures217 Questions
Exam 4: Basic Probability167 Questions
Exam 5: Discrete Probability Distributions165 Questions
Exam 6: The Normal Distribution and Other Continuous Distributions170 Questions
Exam 7: Sampling Distributions165 Questions
Exam 8: Confidence Interval Estimation219 Questions
Exam 9: Fundamentals of Hypothesis Testing: One-Sample Tests194 Questions
Exam 10: Two-Sample Tests240 Questions
Exam 11: Analysis of Variance170 Questions
Exam 12: Chi-Square and Nonparametric188 Questions
Exam 13: Simple Linear Regression243 Questions
Exam 14: Introduction to Multiple394 Questions
Exam 15: Multiple Regression146 Questions
Exam 16: Time-Series Forecasting235 Questions
Exam 17: Getting Ready to Analyze Data386 Questions
Exam 18: Statistical Applications in Quality Management159 Questions
Exam 19: Decision Making126 Questions
Exam 20: Probability and Combinatorics421 Questions
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You were told that the amount of time lapsed between consecutive trades on a foreign stock
exchange market followed a normal distribution with a mean of 15 seconds. You were also told
that the probability that the time lapsed between two consecutive trades to fall between 16 to 17
seconds was 13%. The probability that the time lapsed between two consecutive trades would
fall below 13 seconds was 7%. What is the probability that the time lapsed between two
consecutive trades will be longer than 17 seconds?
(Short Answer)
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SCENARIO 6-6
A recent survey revealed that American's Christmas spending averaged $830. Use this as the
population mean American's Christmas spending. Suppose American's Christmas spending is
normally distributed with a standard deviation of $220.
-Referring to Scenario 6-6, the middle 50% of Americans will spend how much on Christmas?
(Short Answer)
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SCENARIO 6-2
John has two jobs. For daytime work at a jewelry store he is paid $15,000 per month, plus a
commission. His monthly commission is normally distributed with mean $10,000 and standard
deviation $2000. At night he works occasionally as a waiter, for which his monthly income is
normally distributed with mean $1,000 and standard deviation $300. John's income levels from these
two sources are independent of each other.
-Referring to Scenario 6-2, for a given month, what is the probability that John's commission from
the jewelry store is more than $9,500?
(Short Answer)
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A company that sells annuities must base the annual payout on the probability distribution of the
length of life of the participants in the plan. Suppose the probability distribution of the lifetimes
of the participants is approximately a normal distribution with a mean of 68 years and a standard
deviation of 3.5 years. What proportion of the plan recipients die before they reach the standard
retirement age of 65?
(Essay)
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A food processor packages orange juice in small jars. The weights of the filled jars are
approximately normally distributed with a mean of 10.5 ounces and a standard deviation of 0.3
ounce. Find the proportion of all jars packaged by this process that have weights that fall above
10.95 ounces.
(Short Answer)
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SCENARIO 6-3
Suppose the time interval between two consecutive defective light bulbs from a production line has a
uniform distribution over an interval from 0 to 90 minutes.
-Referring to Scenario 6-3, what is the variance of the time interval?
(Short Answer)
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Suppose Z has a standard normal distribution with a mean of 0 and standard deviation of 1. So
85% of the possible Z values are smaller than __________.
(Short Answer)
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SCENARIO 6-2
John has two jobs. For daytime work at a jewelry store he is paid $15,000 per month, plus a
commission. His monthly commission is normally distributed with mean $10,000 and standard
deviation $2000. At night he works occasionally as a waiter, for which his monthly income is
normally distributed with mean $1,000 and standard deviation $300. John's income levels from these
two sources are independent of each other.
-Referring to Scenario 6-2, for a given month, what is the probability that John's income as a
waiter is between $700 and $1600?
(Short Answer)
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You were told that the mean score on a statistics exam is 75 with the scores normally distributed.
In addition, you know the probability of a score between 55 and 60 is 4.41% and that the
probability of a score greater than 90 is 6.68%. The middle 95.46% of the students will score
between which two scores?
(Short Answer)
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The value of the cumulative standardized normal distribution at Z is 0.8770. The value of Z is
(Multiple Choice)
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SCENARIO 6-4
A company producing orange juice buys all its oranges from a large orange orchard. The amount of
juice that can be squeezed from each of these oranges is approximately normally distributed with a
mean of 4.7 ounces and some unknown standard deviation. The company's production manager
knows that the probability is 30.85% that a randomly selected orange will contain less than 4.5
ounces of juice. Also the probability is 10.56% that a randomly selected orange will contain more
than 5.2 ounces of juice. Answer the following questions without the help of a calculator, statistical
software or statistical table.
-Referring to Scenario 6-4, what is the probability that a randomly selected orange will contain
between 4.2 and 4.9 ounces of juices?
(Short Answer)
5.0/5
(39)
SCENARIO 6-6
A recent survey revealed that American's Christmas spending averaged $830. Use this as the
population mean American's Christmas spending. Suppose American's Christmas spending is
normally distributed with a standard deviation of $220.
-Referring to Scenario 6-6, the middle 50% of Americans will spend how much on Christmas?
(Short Answer)
4.9/5
(39)
SCENARIO 6-4
A company producing orange juice buys all its oranges from a large orange orchard. The amount of
juice that can be squeezed from each of these oranges is approximately normally distributed with a
mean of 4.7 ounces and some unknown standard deviation. The company's production manager
knows that the probability is 30.85% that a randomly selected orange will contain less than 4.5
ounces of juice. Also the probability is 10.56% that a randomly selected orange will contain more
than 5.2 ounces of juice. Answer the following questions without the help of a calculator, statistical
software or statistical table.
-Referring to Scenario 6-4, what is the probability that a randomly selected orange will contain
no more than 4.9 ounces of juices?
(Short Answer)
4.9/5
(35)
SCENARIO 6-2
John has two jobs. For daytime work at a jewelry store he is paid $15,000 per month, plus a
commission. His monthly commission is normally distributed with mean $10,000 and standard
deviation $2000. At night he works occasionally as a waiter, for which his monthly income is
normally distributed with mean $1,000 and standard deviation $300. John's income levels from these
two sources are independent of each other.
-Referring to Scenario 6-2, John's income as a waiter will be between what two values
symmetrically distributed around the population mean 90% of the time?
(Short Answer)
4.8/5
(34)
A worker earns $15 per hour at a plant in China and is told that only 2.5% of all
workers make a higher wage. If the wage is assumed to be normally distributed and the standard
deviation of wage rates is $5 per hour, the mean wage for the plant is $7.50 per hour.
(True/False)
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SCENARIO 6-2
John has two jobs. For daytime work at a jewelry store he is paid $15,000 per month, plus a
commission. His monthly commission is normally distributed with mean $10,000 and standard
deviation $2000. At night he works occasionally as a waiter, for which his monthly income is
normally distributed with mean $1,000 and standard deviation $300. John's income levels from these
two sources are independent of each other.
-Referring to Scenario 6-2, John's commission from the jewelry store will be between what two
values symmetrically distributed around the population mean 90% of the time?
(Short Answer)
4.9/5
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The amount of time necessary for assembly line workers to complete a product is a normal
variable with a mean of 15 minutes and a standard deviation of 2 minutes. The probability is
__________ that a product is assembled in less than 12 minutes.
(Short Answer)
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A normal probability plot may be used to assess the assumption of normality for a
particular set of data.
(True/False)
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SCENARIO 6-6
A recent survey revealed that American's Christmas spending averaged $830. Use this as the
population mean American's Christmas spending. Suppose American's Christmas spending is
normally distributed with a standard deviation of $220.
-Referring to Scenario 6-6, what percentage of Americans will spend less than $1,100 or more
than $600 on Christmas?
(Short Answer)
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