Exam 10: Analytic Geometry

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Find the eccentricity of the conic section shown in the graph. - x=21x = - 21  Find the eccentricity of the conic section shown in the graph. - x = - 21

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Solve the problem. -The roof of a building is in the shape of the hyperbola y2x2=27y ^ { 2 } - x ^ { 2 } = 27 , where xx and yy are in meters. Determine the distance, w, between the outside walls. A=11 m\mathrm { A } = 11 \mathrm {~m}  Solve the problem. -The roof of a building is in the shape of the hyperbola  y ^ { 2 } - x ^ { 2 } = 27 , where  x  and  y  are in meters. Determine the distance, w, between the outside walls.  \mathrm { A } = 11 \mathrm {~m}

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The orbit of Mars around the sun is an ellipse with equation x26241+y25184=1\frac { x ^ { 2 } } { 6241 } + \frac { y ^ { 2 } } { 5184 } = 1 where x and y are measured in millions of miles. Find the eccentricity of this ellipse. (Round to the nearest thousandth.)

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Match the equation of the parabola with the appropriate description. - y+6=2(x+10)2y + 6 = 2 ( x + 10 ) ^ { 2 }

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Determine the two equations necessary to graph the horizontal parabola using a graphing calculator. - x=3y2+3x = 3 y ^ { 2 } + 3

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If the vertex of the graph of a quadratic function lies in quadrant I and the graph is concave up, how many xx -intercepts does the graph have?

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Identify the equation as a parabola, circle, ellipse, or hyperbola. - x2y2=16x ^ { 2 } - y ^ { 2 } = 16

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Fill in the blanks to complete the statement. The graph of P(x)=0.1(x4)2\mathrm { P } ( \mathrm { x } ) = - 0.1 ( \mathrm { x } - 4 ) ^ { 2 } is a parabola with ــــــــــ xx -intercept(s). Its vertex is theــــــــــــــ point of the graph and has coordinatesـــــــــــــــــــ

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Give the focus, directrix, and axis for the parabola. - (x+1)2=12(y2)( x + 1 ) ^ { 2 } = 12 ( y - 2 )

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Write an equation for the parabola. -vertex (3,2)( 3,2 ) , focus (3,4)( 3,4 )

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Graph the hyperbola. - (y+2)225(x+1)264=1\frac { ( y + 2 ) ^ { 2 } } { 25 } - \frac { ( x + 1 ) ^ { 2 } } { 64 } = 1  Graph the hyperbola. - \frac { ( y + 2 ) ^ { 2 } } { 25 } - \frac { ( x + 1 ) ^ { 2 } } { 64 } = 1

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Write an equation for the parabola with vertex at the origin. -Focus (15,0)\left( \frac { 1 } { 5 } , 0 \right)

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Solve the problem. -A projectile is thrown upward so that its distance above the ground after tt seconds is h=15t2+540th = - 15 t ^ { 2 } + 540 t . What is its maximum height?

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Write an equation for the parabola. -vertex: (3,4)( - 3 , - 4 ) , directrix: x=8x = - 8

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Write an equation for the hyperbola. -vertices at (0,±10)( 0 , \pm 10 ) , asymptotes at y=±52xy = \pm \frac { 5 } { 2 } x

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Graph the hyperbola. - 25x24y2=10025 x^{2}-4 y^{2}=100  Graph the hyperbola. - 25 x^{2}-4 y^{2}=100

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If the vertex of the graph of a quadratic function lies in quadrant III and the graph is concave up, how many xx -intercepts does the graph have?

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Explain why the vertex of a parabola must lie on its axis.

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Determine the two equations necessary to graph the hyperbola with a graphing calculator. - y216x2=16y ^ { 2 } - 16 x ^ { 2 } = 16

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Graph the parabola. - x=49(y1)24x = \frac { 4 } { 9 } ( y - 1 ) ^ { 2 } - 4  Graph the parabola. - x = \frac { 4 } { 9 } ( y - 1 ) ^ { 2 } - 4

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