Exam 8: Exponential and Logarithmic Functions and Applications

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Evaluate without the use of a calculator. log44\log _ { 4 } 4

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Expand into a sum and/or difference of logarithms. Assume all variables represent positive real numbers. log7xy\log _ { 7 } x ^ { y }

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Write the expression as a single logarithm. Assume all variables represent positive real numbers. 13lna6lnb143lnc\frac { 1 } { 3 } \ln a - 6 \ln b - \frac { 14 } { 3 } \ln c

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ln(a3b6c4c23)\ln \left( \frac { \sqrt [ 3 ] { a } } { b ^ { 6 } c ^ { 4 } \sqrt [ 3 ] { c ^ { 2 } } } \right)

Find the value of logb12\log _ { b } 12 , given that logb3=1.025\log _ { b } 3 = 1.025 and logb4=1.294\log _ { b } 4 = 1.294 .

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Which is a logarithmic function?

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If m(x)=x+4m ( x ) = x + 4 and n(x)=1x+9n ( x ) = \frac { 1 } { x + 9 } find the function value, if possible. (nm)(9)( n \circ m ) ( - 9 )

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Solve the logarithmic equation. log6t4=log6t32\log _ { 6 } t ^ { 4 } = \log _ { 6 } t ^ { 3 } - 2

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The volume of a can that is 12 centimeters (cm) tall is approximated by the function v (r)=37.68r2( r ) = 37.68 r ^ { 2 } , where r is the radius of the can in cm. Chicken soup costs $0.01 per milliliter (mL) and since 1 mL=1 cm31 \mathrm {~mL} = 1 \mathrm {~cm} ^ { 3 } , we can say that chicken soup costs 0.01 per cm30.01 \text { per } \mathrm { cm } ^ { 3 } . The cost to fill a 12 cm tall can with chicken soup is given by C(v) = 0.01v, where v is the volume of the can in cm3\mathrm { cm } ^ { 3 } . a. Find (Cv)(r)( C \circ v ) ( r ) and interpret its meaning in the context of this problem. b. Approximate to the nearest cent the cost to fill a 12 cm can with chicken soup if the can's radius is 5 cm.

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Given that f(x)=2x2+5f ( x ) = 2 x ^ { 2 } + 5 and g(x)=4x+9g ( x ) = 4 x + 9 a. find (fg)(x)( f \circ g ) ( x ) b. find (gf)(x)( g \circ f ) ( x )

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Write an equation of the inverse for the one-to-one function as defined. z(x)=15x2z ( x ) = \frac { 1 } { 5 } x - 2

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Expand into sums and/or differences of logarithms. Assume all variables represent positive real numbers. log(ab3c2)\log \left( \frac { \sqrt [ 3 ] { a b } } { c ^ { 2 } } \right)

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Simplify the expression. Assume all variables represent positive real numbers. 7eln(1y)7 e ^ { \ln ( 1 - y ) }

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Solve the equation. 4y=644 ^ { y } = 64

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Solve the logarithmic equation. log4(c+7)=3\log _ { 4 } ( c + 7 ) = 3

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Write the expression as a single logarithm. Assume all variables represent positive real numbers. 13[log(a2+2a)log(a+2)]\frac { 1 } { 3 } \left[ \log \left( a ^ { 2 } + 2 a \right) - \log ( a + 2 ) \right]

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Solve the exponential equation by taking the logarithm of both sides. 15e0.03m=7515 e ^ { 0.03 m } = 75

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Graph the function f(x)=3xf ( x ) = 3 ^ { x } . Plot at least three points.

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Approximate the function value from the graph. (fg)(0)(f-g)(0)  Approximate the function value from the graph.  (f-g)(0)

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Graph the equation by completing the table and plotting points. Round to two decimal places when necessary. f(x)=3exf(x)=3 e^{x} x y -2 0 1

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Graph the function f(x)=4xf ( x ) = 4 ^ { - x }

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