Exam 7: Quadratic Equations, Functions and Inequalities

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Solve the quadratic equation by completing the square and applying the square root property. k2+14k+50=0k ^ { 2 } + 14 k + 50 = 0

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Solve the equation by using the quadratic formula. 64t2=06 - 4 t ^ { 2 } = 0

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Use the discriminant to determine the type and number of solutions. x(2x + 11) = 40

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Solve the polynomial inequality. Write the answer in interval notation. y2+17>2y- y ^ { 2 } + 17 > - 2 y

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Solve for tt . at2+cz=ba t ^ { 2 } + c z = b

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Solve the inequality. 4y26>2y- 4 y ^ { 2 } - 6 > - 2 y

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Write the coordinates of the vertex and determine if the vertex is a maximum point or a minimum point. f(x)=(x+12)28f ( x ) = ( x + 12 ) ^ { 2 } - 8

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The temperature at a state park for one day in June can be approximated by the function T(x)=0.284x25.11x+820x18T ( x ) = 0.284 x ^ { 2 } - 5.11 x + 82 \quad 0 \leq x \leq 18 where T is degrees Fahrenheit and x is the number of hours after 5 PM on Friday. At what time is the temperature lowest? Round to the nearest hour.

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Solve the equation by using substitution. (t+8)2(t+8)12=0( t + 8 ) ^ { 2 } - ( t + 8 ) - 12 = 0

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Solve the quadratic equation by completing the square and applying the square root property. 73t=2t27 - 3 t = 2 t ^ { 2 }

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Solve the equation by using the square root property. h2=49h ^ { 2 } = 49

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Find the discriminant and use it to determine the number and type of solutions. 5j2=35 j ^ { 2 } = 3

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Solve the equation by using substitution. (2y+4)2=4(2y+4)+7( 2 y + 4 ) ^ { 2 } = 4 ( 2 y + 4 ) + 7

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A model rocket is launched from a raised platform at a speed of 144 feet per second. Its height in feet is given by h(t)=16t2+144t+20h ( t ) = - 16 t ^ { 2 } + 144 t + 20 (t = seconds after launch). After how many seconds does the object reach its maximum height?

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Solve the polynomial inequality. Write the answer in interval notation. 2x217x212 x ^ { 2 } - 17 x \leq - 21

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Solve the quadratic equation by completing the square and applying the square root property. y2+12y1=0y ^ { 2 } + 12 y - 1 = 0

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Find the x- and y-intercepts of the function. p(x)=3x2+5x3p ( x ) = 3 x ^ { 2 } + 5 x - 3

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Graph the function. f(x)=x2+4f ( x ) = x ^ { 2 } + 4

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Write the coordinates of the vertex and determine if the vertex is a maximum point or a minimum point. g(x)=4(x3)2+12g ( x ) = - 4 ( x - 3 ) ^ { 2 } + 12

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Solve the equation by using the quadratic formula. 7x(x2)=57 x ( x - 2 ) = 5

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