Exam 10: Hypothesis Testing Iv Chi Square
Exam 1: Introduction47 Questions
Exam 2: Basic Descriptive Statistics Percentages, Ratios Rates, Tables, Charts Graphs48 Questions
Exam 3: Measures of Central Tendency48 Questions
Exam 4: Measures of Dispersion39 Questions
Exam 5: The Normal Curve42 Questions
Exam 6: Introduction to Inferential Statistics Sampling the Sampling Distribution57 Questions
Exam 7: Hypothesis Testing I the One-Sample Case51 Questions
Exam 8: Hypothesis Testing II the Two-Sample Case49 Questions
Exam 9: Hypothesis Testing III: the Analysis of Variance48 Questions
Exam 10: Hypothesis Testing Iv Chi Square45 Questions
Exam 11: Bivariate Association for Nominal- and Ordinal-Level Variables74 Questions
Exam 12: Association Between Variables Measured at the Interval-Ratio Level45 Questions
Exam 13: Partial Correlation and48 Questions
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Unlike other tests of significance, chi square is based on
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For the chi square test using very large samples, there may be a difference between
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C
The sampling distribution for chi squares is
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In contrast to other tests of significance covered in the text, Chi square is
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According to the text, there is a "gender gap" in American politics and
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When the null hypothesis in the chi square test for independence is true, there should be
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If two variables are independent, the cell frequencies will be
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In a research study conducted to determine if arrests were related to the socioeconomic class of the offender, the chi square critical score was 9.488 and the chi square test statistic was 12.2. We can conclude that
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A Chi square test has been conducted to assess the relationship between marital status and church attendance. The obtained Chi square is 23.45 and the critical Chi square is 9.488. What may be concluded?
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A bivariate table in which one variable had three categories and the other variable had four categories would have
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In the Chi square test for independence, the research hypothesis is
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In the chi square test of hypothesis, the null hypothesis states that the variables are
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In a 2x2 table, all cell frequencies are exactly the same. This is consistent with which of the following conditions?
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Unlike other tests of significance, Chi square easily handles situations in which
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In the Chi square test for independence, the null hypothesis and the research hypothesis
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An obtained chi square of 10.78 has been calculated. Critical Chi square is 3.841. What should be concluded?
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