Exam 11: Alternating-Current Circuits
Exam 1: Electric Fields46 Questions
Exam 2: Gausss Law44 Questions
Exam 3: Electric Potential49 Questions
Exam 4: Energy and Capacitance38 Questions
Exam 5: Current and Resistance33 Questions
Exam 6: Direct-Current Circuits49 Questions
Exam 7: Magnetic Fields45 Questions
Exam 8: Magnetic Forces50 Questions
Exam 9: Faradays Law49 Questions
Exam 10: Inductance23 Questions
Exam 11: Alternating-Current Circuits50 Questions
Exam 12: Electromagnetic Waves40 Questions
Exam 13: The Nature of Light and the Principles of Ray Optics38 Questions
Exam 14: Image Formation45 Questions
Exam 15: Wave Optics43 Questions
Exam 16: Diffraction Patterns and Polarisation44 Questions
Exam 17: Quantisation and Wave-Particle Duality41 Questions
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A 10.0- resistor, 10.0-mH inductor, and 10.0- F capacitor are connected in series with a 10.0-kHz voltage source.The rms current through the circuit is 0.200 A.Find the rms voltage drop across each of the 3 elements.
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The primary winding of an electric train transformer has 400 turns and the secondary has 50.If the input voltage is 120V(rms) what is the output voltage?
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Determine the rms voltage drop across the inductor in the circuit. 

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For driving voltage V = Vm sin t, the current through the resistor is:

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The average power input to a series alternating current circuit is minimum when:
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The graphs below show the phasors Vmax and Imax for five RLC series circuits.The solid arrows represent the voltage phasors, V, and the dashed arrows represent the current phasors, Imax.The graph which represents a circuit where the capacitive reactance is greater than the inductive reactance is:
(Multiple Choice)
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A 60.0-Hz ac generator with a peak voltage of 110 V drives a series RL circuit with R = 10.0 and L = 10.0 mH.The impedance is:
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The inductance of a tuning circuit of an AM radio is 4.00 mH.Find the capacitance of the circuit required for reception at 1200 kHz.
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In a typical transmission line, the current I is very small and the voltage V is very large.A unit length of line has resistance R.For a power line that supplies power to 10 000 households, we can conclude that:
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