Exam 12: Conic Sections

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Find an equation for the conic whose graph is shown. Find an equation for the conic whose graph is shown.

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Sketch the graph of the ellipse. (x3)29+y236=1\frac { ( x - 3 ) ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 36 } = 1

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Find an equation of the parabola whose graph is shown. Find an equation of the parabola whose graph is shown.

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Find an equation for the parabola with vertex (5,5)( 5,5 ) and directrix yaxisy - a x i s .

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Find an equation for the parabola with vertex (5,5)( 5,5 ) and directrix y axis y - \text { axis } .

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Determine the XY\overline { X Y } - coordinates of (2,5)( - 2,5 ) if the axes are rotated through an angle ϕ=30\phi = 30 ^ { \circ } .

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Find an equation for the conic whose graph is shown. Find an equation for the conic whose graph is shown.

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Find the vertices and foci for the ellipse. y2=42x2y ^ { 2 } = 4 - 2 x ^ { 2 }

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Write a polar equation of a hyperbola with eccentricity 33 and directrix r=2cscθr = 2 \csc \theta

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Find the vertices of the hyperbola. 16y24x2=6416 y ^ { 2 } - 4 x ^ { 2 } = 64

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Find the vertices and foci for the ellipse. y2=42x2y ^ { 2 } = 4 - 2 x ^ { 2 }

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Find the vertices of the hyperbola. 16y24x2=6416 y ^ { 2 } - 4 x ^ { 2 } = 64

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Find an equation for the ellipse with center at the origin, major axis of length 272 \sqrt { 7 } , minor axis of length 232 \sqrt { 3 } , and whose foci lie on the yy -axis.

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Find the vertex, and directrix of the parabola. y2+2y12x+37=0y ^ { 2 } + 2 y - 12 x + 37 = 0

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Find an equation for the conic whose graph is shown. Find an equation for the conic whose graph is shown.

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Find an equation of the parabola whose graph is shown. Find an equation of the parabola whose graph is shown.

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Find an equation for the conic whose graph is shown. Find an equation for the conic whose graph is shown.

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Find an equation for the conic whose graph is shown. Find an equation for the conic whose graph is shown.

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Complete the square to determine the type of curve represented by the equation. x2+6x3y2+12y=12x ^ { 2 } + 6 x - 3 y ^ { 2 } + 12 y = 12

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A cannon fires a cannonball as shown in the figure. The path of the cannonball is a parabola with vertex at the highest point of the path. If the cannonball lands 1600 ft from the cannon and the highest point it reaches is 2400 ft above the ground, find an equation for the path of the cannonball. Place the origin at the location of the cannon. A cannon fires a cannonball as shown in the figure. The path of the cannonball is a parabola with vertex at the highest point of the path. If the cannonball lands 1600 ft from the cannon and the highest point it reaches is 2400 ft above the ground, find an equation for the path of the cannonball. Place the origin at the location of the cannon.

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