Question 1

One milliliter is equal to _____.

Accepted Answer

A)  2.54 cubic inches 
B)  1000 liters 
C)  1 cubic centimeter 
D)  16.39 cubic inches 
E)  0.6214 cubic inches 
A)  2.54 cubic inches 
B)  1000 liters 
C)  1 cubic centimeter 
D)  16.39 cubic inches 
E)  0.6214 cubic inches

Question 2

A regulation soccer field is 110.0 yards in length. Calculate the length in millimeters. (1.094 yards = 1 m)

Accepted Answer

A)  0.101 mm 
B)  1.01 mm 
C)  100.5 mm 
D)  1.01 × 104 mm 
E)  1.01 × 105 mm 
A)  0.101 mm 
B)  1.01 mm 
C)  100.5 mm 
D)  1.01 × 104 mm 
E)  1.01 × 105 mm

Question 3

Chloroform is a commonly used anesthetic with a density of 1.483 g/mL. Determine the volume of chloroform needed to administer a 9.37 g sample of the anesthetic.

Accepted Answer

A)  0.158 g 
B)  6.32 g 
C)  13.9 g 
D)  13.89 g 
E)  0.0632 g 
A)  0.158 g 
B)  6.32 g 
C)  13.9 g 
D)  13.89 g 
E)  0.0632 g

Question 4

Solve the problem. ​
33.5 ÷ 3.011 = _____

Accepted Answer

A)  1.11 × 101 
B)  1.11 × 103 
C)  1.113 × 101 
D)  1.11 × 102 
E)  1.112587 × 101 
A)  1.11 × 101 
B)  1.11 × 103 
C)  1.113 × 101 
D)  1.11 × 102 
E)  1.112587 × 101

Question 5

Which of these is the correct normal decimal notation for 5.23 × 10 − 4?

Accepted Answer

A)  0.0523 
B)  0.00523 
C)  0.0000523 
D)  0.000523 
E)  52,300 
A)  0.0523 
B)  0.00523 
C)  0.0000523 
D)  0.000523 
E)  52,300

Question 6

Determine the density of a 50.0 g sample of mercury having a volume of 3.66 mL. Carry out the calculation to the correct number of significant digits .

Accepted Answer

A)  13.66 g/mL 
B)  13.7 mL 
C)  183 g/mL 
D)  0.0732 g/mL 
E)  0.073 g/mL 
A)  13.66 g/mL 
B)  13.7 mL 
C)  183 g/mL 
D)  0.0732 g/mL 
E)  0.073 g/mL

Question 7

Solve the problem. ​
(5.46 × 107 + 3.13 × 106) × (7.65 × 105) = _____

Accepted Answer

A)  65.7 × 1018 
B)  130.7 × 1018 
C)  4.42 × 1013 
D)  2.39 × 1012 
E)  65.7 × 108 
A)  65.7 × 1018 
B)  130.7 × 1018 
C)  4.42 × 1013 
D)  2.39 × 1012 
E)  65.7 × 108

Question 8

Which of these represents the SI prefix for micro ( μ )?

Accepted Answer

A)  10 − 6 
B)  10 − 3 
C)  10 − 9 
D)  10 − 2 
E)  106 
A)  10 − 6 
B)  10 − 3 
C)  10 − 9 
D)  10 − 2 
E)  106

Question 9

Solve the problem. ​
(3.21 × 1010 − 3.13 × 1012) ÷ (7.65 × 105) = _____

Accepted Answer

A)  4.13 × 106 
B)  2.37 × 1018 
C)  65.7 × 1018 
D)  − 23.7 × 1017 
E)  − 4.04 × 106 
A)  4.13 × 106 
B)  2.37 × 1018 
C)  65.7 × 1018 
D)  − 23.7 × 1017 
E)  − 4.04 × 106

Question 10

Convert 89.5 m to millimeters.

Accepted Answer

A)  8.95 × 104 mm 
B)  8.95 × 10 − 4 mm 
C)  8.95 × 102 mm 
D)  8.95 × 10 − 2 mm 
E)  8.95 × 105 mm 
A)  8.95 × 104 mm 
B)  8.95 × 10 − 4 mm 
C)  8.95 × 102 mm 
D)  8.95 × 10 − 2 mm 
E)  8.95 × 105 mm

Question 11

How many significant figures are there in the number 10,100?

Accepted Answer

A)  1 
B)  3 
C)  4 
D)  5 
E)  0 
A)  1 
B)  3 
C)  4 
D)  5 
E)  0

Question 12

The equivalent of 1 m is _____.

Accepted Answer

A)  3.54 in 
B)  5.6 in 
C)  2.5 in 
D)  39.37 in 
E)  31.35 in 
A)  3.54 in 
B)  5.6 in 
C)  2.5 in 
D)  39.37 in 
E)  31.35 in

Question 13

A 5 ft 7 in track athlete weighs 110 pounds. What is her height in cm and her weight in kilograms? (2.54 cm = 1 inch; 454 g = 1 pound)

Accepted Answer

A)  14.5 cm and  242 kg 
B)  152 cm and  49.9 kg 
C)  170 cm and  49.9 kg 
D)  154 cm and  242 kg 
E)  152 cm and  4.99 × 104 kg 
A)  14.5 cm and  242 kg 
B)  152 cm and  49.9 kg 
C)  170 cm and  49.9 kg 
D)  154 cm and  242 kg 
E)  152 cm and  4.99 × 104 kg

Question 14

A football field is 100 yd long. What is its length in centimeters? (1 yd = 0.9144 m)

Accepted Answer

A)  0.09144 cm 
B)  91.44 cm 
C)  274.32 cm 
D)  334 cm 
E)  9.144 × 103 cm 
A)  0.09144 cm 
B)  91.44 cm 
C)  274.32 cm 
D)  334 cm 
E)  9.144 × 103 cm

Question 15

Solve the problem. ​
131.7 × 1.05 = _____

Accepted Answer

A)  1.38 × 103 
B)  1.38 × 102 
C)  1.3 × 103 
D)  1.30 × 103 
E)  1.3 × 10 − 3 
A)  1.38 × 103 
B)  1.38 × 102 
C)  1.3 × 103 
D)  1.30 × 103 
E)  1.3 × 10 − 3

Question 16

Which of these numbers has four significant figures?

Accepted Answer

A)  0.3211 
B)  0.201 
C)  6.02 × 1023 
D)  510 
E)  0.0103 
A)  0.3211 
B)  0.201 
C)  6.02 × 1023 
D)  510 
E)  0.0103

Question 17

Convert 2.50 × 10  4  meters to miles. (1 km = 0.62137 mile)

Accepted Answer

A)  76.2 miles 
B)  6.35 miles 
C)  15.5 miles 
D)  155 miles 
E)  186 miles 
A)  76.2 miles 
B)  6.35 miles 
C)  15.5 miles 
D)  155 miles 
E)  186 miles

Question 18

Which of these represents the SI prefix for centi (c)?

Accepted Answer

A)  10 − 6 
B)  10 − 3 
C)  10 − 1 
D)  10 − 2 
E)  10  2  
A)  10 − 6 
B)  10 − 3 
C)  10 − 1 
D)  10 − 2 
E)  10  2

One milliliter is equal to _____.

A regulation soccer field is 110.0 yards in length. Calculate the length in millimeters. (1.094 yards = 1 m)

Chloroform is a commonly used anesthetic with a density of 1.483 g/mL. Determine the volume of chloroform needed to administer a 9.37 g sample of the anesthetic.

Solve the problem. 33.5 ÷ 3.011 = _____

Which of these is the correct normal decimal notation for 5.23 × 10^{− 4}?

Determine the density of a 50.0 g sample of mercury having a volume of 3.66 mL. Carry out the calculation to the correct number of significant digits .

Solve the problem. (5.46 × 10⁷ + 3.13 × 10⁶) × (7.65 × 10⁵) = _____

Which of these represents the SI prefix for micro ( μ )?

Solve the problem. (3.21 × 10¹⁰ − 3.13 × 10¹²) ÷ (7.65 × 10⁵) = _____

Convert 89.5 m to millimeters.

How many significant figures are there in the number 10,100?

The equivalent of 1 m is _____.

A 5 ft 7 in track athlete weighs 110 pounds. What is her height in cm and her weight in kilograms? (2.54 cm = 1 inch; 454 g = 1 pound)

A football field is 100 yd long. What is its length in centimeters? (1 yd = 0.9144 m)

Solve the problem. 131.7 × 1.05 = _____

Which of these numbers has four significant figures?

Convert 2.50 × 10 ⁴ meters to miles. (1 km = 0.62137 mile)

Which of these represents the SI prefix for centi (c)?

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Exam 2: The Chemists Toolbox

One milliliter is equal to _____.

A regulation soccer field is 110.0 yards in length. Calculate the length in millimeters. (1.094 yards = 1 m)

Chloroform is a commonly used anesthetic with a density of 1.483 g/mL. Determine the volume of chloroform needed to administer a 9.37 g sample of the anesthetic.

Solve the problem. ​ 33.5 ÷ 3.011 = _____

Which of these is the correct normal decimal notation for 5.23 × 10 − 4?

Determine the density of a 50.0 g sample of mercury having a volume of 3.66 mL. Carry out the calculation to the correct number of significant digits .

Solve the problem. ​ (5.46 × 107 + 3.13 × 106) × (7.65 × 105) = _____

Which of these represents the SI prefix for micro ( μ )?

Solve the problem. ​ (3.21 × 1010 − 3.13 × 1012) ÷ (7.65 × 105) = _____

Convert 89.5 m to millimeters.

How many significant figures are there in the number 10,100?

The equivalent of 1 m is _____.

A 5 ft 7 in track athlete weighs 110 pounds. What is her height in cm and her weight in kilograms? (2.54 cm = 1 inch; 454 g = 1 pound)

A football field is 100 yd long. What is its length in centimeters? (1 yd = 0.9144 m)

Solve the problem. ​ 131.7 × 1.05 = _____

Which of these numbers has four significant figures?

Convert 2.50 × 10 4 meters to miles. (1 km = 0.62137 mile)

Which of these represents the SI prefix for centi (c)?

Molecular Reasons

Atoms and Elements

Molecules, Compounds, and Chemical Reactions

Chemical Bonding

Organic Chemistry

Light and Color

Nuclear Chemistry

Energy for Today

Energy for Tomorrow: Solar and Other Renewable Energy Sources

The Air Around Us

The Liquids and Solids Around Us: Especially Water

Acids and Bases: the Molecules Responsible for Sour and Bitter

Oxidation and Reduction

The Chemistry of Household Products

Biochemistry and Biotechnology

Drugs and Medicine: Healing, Helping, and Hurting

The Chemistry of Food

Nanotechnology Online Only

Filters

Solve the problem. 33.5 ÷ 3.011 = _____

Which of these is the correct normal decimal notation for 5.23 × 10^{− 4}?

Solve the problem. (5.46 × 10⁷ + 3.13 × 10⁶) × (7.65 × 10⁵) = _____

Solve the problem. (3.21 × 10¹⁰ − 3.13 × 10¹²) ÷ (7.65 × 10⁵) = _____

Solve the problem. 131.7 × 1.05 = _____

Convert 2.50 × 10 ⁴ meters to miles. (1 km = 0.62137 mile)