Exam 6: Equations and Formulas

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Solve the formula for the given letter. I=VR for RI = \frac { V } { R } \text { for } R

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Cut a board 36 ft long into three pieces so that the longest piece will be twice as long as each of the other two of equal lengths. Find the length of each piece.

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Use the formula 1R=1R1+1R2\frac { 1 } { R } = \frac { 1 } { R _ { 1 } } + \frac { 1 } { R _ { 2 } } . Given R = 12 ? and R2R _ { 2 } = 36 ?. Find R1R _ { 1 } .

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Solve the formula for the given letter.   CT=C1+C2+C3+C4 for C4C _ { T } = C _ { 1 } + C _ { 2 } + C _ { 3 } + C _ { 4 } \text { for } C _ { 4 }

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Solve the equation and check. 8x4=138 x - 4 = 13

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Solve the formula for the given letter. S=a+b2h for S = \frac { a + b } { 2 } h \text { for }

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Solve the equation and check. 2x37=x2\frac { 2 x } { 3 } - 7 = - \frac { x } { 2 } x = __________

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Follow the rules for working with measurements. A flashlight bulb is connected to a 1.5V1.5 - V source. Its current, I, is 0.29 A0.29 \mathrm {~A} What is its resistance, R, in ohms? V = IR .

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A 9-quart cooling system is checked and found to be filled with a solution that is 10% antifreeze. The desired strength of the solution is 70% antifreeze. How many quarts of solution need to be drained and replaced with pure antifreeze to reach the desires strength?

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Solve the equation and check. 2x2=3x112 x - 2 = 3 x - 11 x = __________

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Use the formula 1f=1s0+1si\frac { 1 } { f } = \frac { 1 } { s _ { 0 } } + \frac { 1 } { s _ { i } } . Given s0s 0 = 27.5 cm and SiS _ { i } = 38.5 cm, find f.

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Solve the equation and check. x97=8\frac { x } { 9 } - 7 = 8 x = __________

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Solve the equation and check. x=60- x = 60 x = __________

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Solve the equation and check. 9x10+15(10+x)=57\frac { 9 x } { 10 } + \frac { 1 } { 5 } ( 10 + x ) = 57

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Solve the equation and check. 92x+2512=9x15\frac { 9 } { 2 x } + 25 \frac { 1 } { 2 } = \frac { 9 } { x } - 15

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Solve the formula for the given letter. XC=12πfC for fX _ { C } = \frac { 1 } { 2 \pi f C } \text { for } f

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Use the formula 1R=1R1+1R2+1R3\frac { 1 } { R } = \frac { 1 } { R _ { 1 } } + \frac { 1 } { R _ { 2 } } + \frac { 1 } { R _ { 3 } } . Given R=1,150ΩR = 1,150 \Omega , R1=3,850ΩR _ { 1 } = 3,850 \Omega and R3=4,250ΩR _ { 3 } = 4,250 \Omega . Find R2R _ { 2 } .

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Solve the equation and check. 11x12+16(12+x)=54\frac { 11 x } { 12 } + \frac { 1 } { 6 } ( 12 + x ) = 54 x = __________

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Solve the equation and check. 14y+8=8y14- 14 y + 8 = 8 y - 14

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Solve the formula for the given letter. νf=νi+ at for νi\nu _ { f } = \nu _ { i } + \text { at for } \nu _ { i }

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