Exam 6: Equations and Formulas

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Solve the equation and check. 12x=107x571 - \frac { 2 } { x } = \frac { 10 } { 7 x } - \frac { 5 } { 7 } x = __________

(Short Answer)
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Solve the formula for the given letter. Q=I2RtJ for RQ = \frac { I ^ { 2 } R t } { J } \text { for } R

(Multiple Choice)
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Solve the equation and check. 64m=064 m = 0

(Multiple Choice)
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Solve the equation and check. 4(9y2)+3(2y+6)=25(3y+2)123y4 ( 9 y - 2 ) + 3 ( 2 y + 6 ) = 25 ( 3 y + 2 ) - 123 y

(Multiple Choice)
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Solve the equation and check. 4x = 2x - 2828

(Multiple Choice)
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Given the formula: A=12h(a+b),A=2,690,h=62,a=43.2A = \frac { 1 } { 2 } h ( a + b ) , A = 2,690 , \quad h = 62 , \quad a = 43.2 Find b.

(Multiple Choice)
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Solve the equation and check. 0.095x0.285+0.001(5x)=0.2620.095 x - 0.285 + 0.001 ( 5 - x ) = 0.262

(Essay)
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Solve the equation and check. 23x=2623 - x = 26   x=x= ________

(Short Answer)
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Use the formula 1R=1R1+1R2+1R3\frac { 1 } { R } = \frac { 1 } { R _ { 1 } } + \frac { 1 } { R _ { 2 } } + \frac { 1 } { R _ { 3 } } . Given R=155ΩR = 155 \Omega , R2=900ΩR _ { 2 } = 900 \Omega and R3=690ΩR _ { 3 } = 690 \Omega . Find R1R _ { 1 } .

(Multiple Choice)
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Given the formula: A = P + Prt, r=0.06,P=$5,900,A=$7,025r = 0.06 , P = \$ 5,900 , A = \$ 7,025 . Find t.

(Multiple Choice)
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Solve the equation and check. 9x+6x618+10x+77=769 x + \frac { 6 x - 6 } { 18 } + \frac { 10 x + 7 } { 7 } = 76

(Multiple Choice)
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Solve the equation and check. x23=1.5\frac { x } { 23 } = 1.5

(Multiple Choice)
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Solve the equation and check. 76w=1017 - 6 w = - 101

(Multiple Choice)
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Solve the equation and check. Give your answer as a fraction. 20=417t20 = - 4 - 17 t

(Essay)
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Solve the equation and check. y63=y12\frac { y } { 6 } - 3 = \frac { y } { 12 } y = __________

(Short Answer)
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Solve the equation and check. 5x+1=7x95 x + 1 = 7 x - 9 x = __________

(Short Answer)
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Solve the equation and check. 513y=2913\frac { 5 } { 13 } y = 2 \frac { 9 } { 13 } y = __________

(Short Answer)
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Use the formula 1R=1R1+1R2+1R3\frac { 1 } { R } = \frac { 1 } { R _ { 1 } } + \frac { 1 } { R _ { 2 } } + \frac { 1 } { R _ { 3 } } . Given R=75ΩR = 75 \Omega , R1=165ΩR _ { 1 } = 165 \Omega  and R2=275ΩR _ { 2 } = 275 \Omega Find R3R _ { 3 } .

(Multiple Choice)
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Given the formula: L=π(r1+r2)+2d,L=56.97,d=5.46,r2=6L = \pi \left( r _ { 1 } + r _ { 2 } \right) + 2 d , L = 56.97 , d = 5.46 , r _ { 2 } = 6 Find r1r_ { 1} .

(Multiple Choice)
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Solve the equation and check. 7x5=4\frac { 7 } { x } - 5 = - 4 x = __________

(Short Answer)
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