Exam 5: The Normal Curve and Standard Scores

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In a plot of the normal curve, frequency is plotted on the X axis.

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If the mean height of college males is 70 inches with a standard deviation of 3 inches, what percentage of college males would be between 6' and 6'4"? Assume a normal distribution.

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In a normal curve, the area contained between the mean and a score that is 2.30 standard deviations above the mean is 0.4893 of the total area.

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In a population survey of patients in a rehabilitation hospital, the mean length of stay in the hospital was 12.0 weeks with a standard deviation equal to 1.0 week. The distribution was normally distributed. What is the length of stay at the 50th percentile?

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An economics test was given and the following sample scores were recorded: An economics test was given and the following sample scores were recorded:   The z score for individual D is _________. The z score for individual D is _________.

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Define asymptotic.

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S ( z - µz ) equals _________.

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A stockbroker has kept a daily record of the value of a particular stock over the years and finds that prices of the stock form a normal distribution with a mean of $8.52 with a standard deviation of $2.38. The stock price beyond which 0.05 of the distribution falls is _________.

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Is a z distribution always normally shaped? Explain.

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The mean of the z distribution equals _________.

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If the original raw score distribution has a mean that is not equal to zero, the mean of the z transformed scores will not equal zero either.

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In a population survey of patients in a rehabilitation hospital, the mean length of stay in the hospital was 12.0 weeks with a standard deviation equal to 1.0 week. The distribution was normally distributed. What is the length of stay at the 90th percentile?

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The normal curve reaches the horizontal axis in 4 standard deviations above and below the mean.

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In a population survey of patients in a rehabilitation hospital, the mean length of stay in the hospital was 12.0 weeks with a standard deviation equal to 1.0 week. The distribution was normally distributed. What percentage of patients would you expect to stay between 11.5 weeks and 13.0 weeks?

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The mean of the z distribution equals _________.

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In a population survey of patients in a rehabilitation hospital, the mean length of stay in the hospital was 12.0 weeks with a standard deviation equal to 1.0 week. The distribution was normally distributed. What proportion of patients are likely to be in less than 9.7 weeks?

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The z distribution takes on the same shape as the raw scores.

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In a population survey of patients in a rehabilitation hospital, the mean length of stay in the hospital was 12.0 weeks with a standard deviation equal to 1.0 week. The distribution was normally distributed. How many times out of 10,000 would you expect a patient selected at random to remain in the hospital longer than 14.6 weeks?

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Does the z transformation result in a score having the same units of measurement as the raw score? Explain. Why is this advantageous?

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List three characteristics of a z distribution.

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