Question 1

Solve the equation: $( 5 y - 2 ) ( y + 7 ) = 0$

Accepted Answer

A)  $- \frac { 2 } { 5 } , 7$ 
B)  $- 7 , \frac { 2 } { 5 }$ 
C)  $- 7,2$ 
D)  $- 5 , \frac { 2 } { 7 }$ 
A)  $- \frac { 2 } { 5 } , 7$ 
B)  $- 7 , \frac { 2 } { 5 }$ 
C)  $- 7,2$ 
D)  $- 5 , \frac { 2 } { 7 }$

Question 2

Factor the polynomial. $$9 - y ^ { 2 } c ^ { 2 }$$

Accepted Answer

A)  $( 3 + y c ) ( 3 - y c )$ 
B)  $( 3 - y c ) ( 3 - y c )$ 
C)  $( 3 + y c ) ( 3 + y c )$ 
D)  $( 2 - y c ) ( 3 - y c )$ 
E)  $( 2 + y c ) ( 3 - y c )$ 
A)  $( 3 + y c ) ( 3 - y c )$ 
B)  $( 3 - y c ) ( 3 - y c )$ 
C)  $( 3 + y c ) ( 3 + y c )$ 
D)  $( 2 - y c ) ( 3 - y c )$ 
E)  $( 2 + y c ) ( 3 - y c )$

Solve the equation: $( 5 y - 2 ) ( y + 7 ) = 0$

Factor the polynomial. $9 - y ^ { 2 } c ^ { 2 }$

An Introduction to Algebra

Equations, Inequalities, and Problem Solving

Graphs, Linear Equations, and Inequalities in Two Variables; Functions From Campus to Careers: Physical Therapis

Solving Systems of Equations and Inequalities

Exponents and Polynomials

Rational Expressions and Equations

Roots and Radicals

Quadratic Equations

Filters

Exam 6: Factoring and Quadratic Equations

Solve the equation: (5y−2)(y+7)=0( 5 y - 2 ) ( y + 7 ) = 0(5y−2)(y+7)=0

Factor the polynomial. 9−y2c29 - y ^ { 2 } c ^ { 2 }9−y2c2

An Introduction to Algebra

Equations, Inequalities, and Problem Solving

Graphs, Linear Equations, and Inequalities in Two Variables; Functions From Campus to Careers: Physical Therapis

Solving Systems of Equations and Inequalities

Exponents and Polynomials

Rational Expressions and Equations

Roots and Radicals

Quadratic Equations

Filters

Solve the equation: $( 5 y - 2 ) ( y + 7 ) = 0$

Factor the polynomial. $9 - y ^ { 2 } c ^ { 2 }$