Exam 2: Linear and Absolute Value Equations and Inequalities

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Simplify, where possible - 10x6x10 x-6 x

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Write an inequality associated with the given interval notation - (,16)(-\infty, 16)

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Simplify, where possible - 6a4b+26 a-4 b+2

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Solve the inequality. Graph your solution on a number line, and write your solution in interval notation - 8x+32>0|8 x+3|-2>0  Solve the inequality. Graph your solution on a number line, and write your solution in interval notation - |8 x+3|-2>0

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The sum of the measures of the angles of any triangle is 180180^{\circ} . In triangle ABCA B C , angles AA and BB have the same measure, while the measure of angle C\mathrm{C} is 6060^{\circ} larger than each of A\mathrm{A} and B\mathrm{B} . What are the measures of the three angles?

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Graph the inequality - x4\mathrm{x} \leq 4

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Graph the solution on a number line, and express it in interval notation. - 12x391 \leq 2 x-3 \leq 9  Graph the solution on a number line, and express it in interval notation. - 1 \leq 2 x-3 \leq 9

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Write the inequality in interval notation - 7.5<x0.1-7.5< x \leq-0.1

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n+812=107\frac{n+8}{12}=\frac{10}{7}

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6x+2+6=9|6 x+2|+6=9

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Graph the solution on a number line, and express it in interval notation. - 16<4x2016<4 \mathrm{x} \leq 20  Graph the solution on a number line, and express it in interval notation. - 16<4 \mathrm{x} \leq 20

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Convert the given quantity to the desired unit. Round to the nearest tenth if necessary - 49 g49 \mathrm{~g} to oz

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If 3 is added to a number and the sum is doubled, the result is 11 less than the number. Find the number.

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Classify the absolute value inequality as · Having a single interval containing its solutions, but not the entire set of real numbers · Having the union of two disjoint intervals containing its solutions · Being a contradiction with no solution · Being an identity with the set of all real numbers as its solution set - 4x183|4 \mathrm{x}-1|-8 \leq 3

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Graph the solution on a number line, and express it in interval notation. - 33+12x4-3 \leq 3+\frac{1}{2} \mathrm{x} \leq 4  Graph the solution on a number line, and express it in interval notation. - -3 \leq 3+\frac{1}{2} \mathrm{x} \leq 4

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Classify the absolute value equation as being a contradiction with no solution or as having two solutions. - 5x111=4|5 \mathrm{x}-1|-11=-4

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5(2z5)=9(z+5)5(2 z-5)=9(z+5)

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Convert the given quantity to the desired unit. Round to the nearest tenth if necessary - 27in.27 \mathrm{in.} to cm\mathrm{cm}

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Evaluate the algebraic expression under the given conditions - 6(x+h)+76(x+h)+7 for x=6x=6 and h=0.001h=0.001

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Simplify, where possible - 3xy9(4x8y)3 x-y-9(4 x-8 y)

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