\[\begin{array} { l c c c c } \text { Source } & \text { SS } & \text { DF } & \text { MS } & \text { F } \\ \text { Factor A } & 2.25 & & .75 & \\ \text { Factor B } & .95 & & .95 & \\ \text { Interaction } & .90 & 3 & & \\ \text { Error } & & & .15 & \\ \text { Total } & 6.5 & 23 & \end{array}\] -Given the partial ANOVA table above,the number of levels of factor A are ____ and the number of levels factor B are ___.

A) 3,1 B) 4,2 C) 6,1 D) 4,24 E) 1,16 A) 3,1 B) 4,2 C) 6,1 D) 4,24 E) 1,16

Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments). \[\begin{array} { l c } \text { Source } & \text { Sum of Squares } \\ \text { Treatments } & 15.93 \\ \text { Blocks } & 42.09 \\ \text { Error } & 23.84 \\ \text { Total } & 81.86 \end{array}\] -What is the calculated F statistic for blocks?

The answer of Consider the following partial analysis of variance...

Exam 10: Experimental Design and Analysis of Variance

Determine degrees of freedom treatment,degrees of freedom error,and degrees of freedom total and state the critical value of the F statistic at a = .05

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Question 61

In one-way ANOVA,the denominator of the F statistic is an estimate of the constant population variance of the treatment groups.

(True/False)

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Question 62

Looking at four different diets,a researcher randomly assigned 20 equally overweight adults into each of the four diets.The response was weight loss,in kilograms.The MSE = 31.4 and $\bar { x }$ = 14.25, $\overline { x _ { 1 } } = 10.6$ , $\bar { x } _ { 2 } = 12.8$ , $\bar { x } _ { 3 } = 12.4$ , $\bar { x } _ { 4 } = 21.2$ . -Compute a 95% confidence interval for the second group (diet)mean

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Question 63

In performing a two-way ANOVA for a two-factor factorial experiment,the interaction sum of squares,SS(int),equals:

(Multiple Choice)

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Question 64

A completely randomized design with three groups,each with five measurements.The one-way ANOVA yields a between-groups sum of squares treatment of 17.0493 and error sum of squares of 8.028.Compute the F statistic.

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Question 65

Consider the following partial analysis of variance table from a randomized block design with 10 blocks and 6 groups (treatments). Source SS Treatments 2,477.53 Blocks 3,180.48 Error 11,661.38 Total -What is the error mean square?

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Question 66

Source SS DF MS F Factor A 2.25 .75 Factor B .95 .95 Interaction .90 3 Error .15 Total 6.5 23 -Given the partial ANOVA table above,the number of levels of factor A are __ and the number of levels factor B are _.

(Multiple Choice)

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Question 67

Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments). Source Sum of Squares Treatments 15.93 Blocks 42.09 Error 23.84 Total 81.86 -What is the calculated F statistic for blocks?

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Question 68

Find Tukey's simultaneous 95 percent confidence interval for $\mu _ { 1 } - \mu _ { 2 }$ where $\bar { x } _ { 1 }$ = 51.5, $\bar { x } _ { 2 }$ = 55.8,and MSE = 6.125.There were 4 treatments and 24 observations in total and the number of observations were equal in each group.

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Question 69

When computing Tukey simultaneous confidence intervals for all possible pairwise comparisons of the treatment group means,the experimentwise error rate will be

(Multiple Choice)

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Question 70

When computing individual confidence intervals based on the t distribution for all possible pairwise comparisons of the treatment group means,the experimentwise error rate will be

(Multiple Choice)

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Question 71

In performing a two-way ANOVA for a two-factor factorial experiment under which of the following circumstances would we test the significance of the main effects?

(Multiple Choice)

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Question 72

Test H₀: there is no interaction between Factor I and Factor II at a =.05.

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Question 73

Suppose that you analyze data from a randomized block experimental design using ANOVA.At the 5% level of significance,you reject the null hypothesis of equal treatment group means.You find out later that the data was actually from a completely randomized experimental design and use the one-way ANOVA procedure to reanalyze the data.For the completely randomized design ANOVA,the null hypothesis of equal treatment group means will ______ be rejected.

(Multiple Choice)

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Question 74

Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments). Source Sum of Squares Treatments 15.93 Blocks 42.09 Error 23.84 Total 81.86 -Test H₀: there is no difference between treatment effects at a =.05.

(Essay)

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Question 75

Looking at four different diets,a researcher randomly assigned 20 equally overweight adults into each of the four diets.The response was weight loss,in kilograms.The MSE = 31.4 and $\bar { x }$ = 14.25, $\overline { x _ { 1 } } = 10.6$ , $\bar { x } _ { 2 } = 12.8$ , $\bar { x } _ { 3 } = 12.4$ , $\bar { x } _ { 4 } = 21.2$ . -Compute a 95% confidence interval for the fourth group (diet)mean.

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Question 76

When using a randomized block design,each block is used exactly once to measure the effect of each and every treatment.

(True/False)

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Question 77

In performing a two-way ANOVA for a two-factor factorial experiment,the error sum of squares,SSE,equals:

(Multiple Choice)

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Question 78

In performing a two-way ANOVA for a two-factor factorial experiment,we first test the _________.

(Multiple Choice)

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Question 79

The advantage of the randomized block design over the completely randomized design is that we are comparing the treatments by using ________ experimental units.

(Multiple Choice)

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Question 80

Determine degrees of freedom treatment,degrees of freedom error,and degrees of freedom total and state the critical value of the F statistic at a = .05

In one-way ANOVA,the denominator of the F statistic is an estimate of the constant population variance of the treatment groups.

In performing a two-way ANOVA for a two-factor factorial experiment,the interaction sum of squares,SS(int),equals:

A completely randomized design with three groups,each with five measurements.The one-way ANOVA yields a between-groups sum of squares treatment of 17.0493 and error sum of squares of 8.028.Compute the F statistic.

Consider the following partial analysis of variance table from a randomized block design with 10 blocks and 6 groups (treatments). Source SS Treatments 2,477.53 Blocks 3,180.48 Error 11,661.38 Total -What is the error mean square?

Source SS DF MS F Factor A 2.25 .75 Factor B .95 .95 Interaction .90 3 Error .15 Total 6.5 23 -Given the partial ANOVA table above,the number of levels of factor A are __ and the number of levels factor B are _.

Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments). Source Sum of Squares Treatments 15.93 Blocks 42.09 Error 23.84 Total 81.86 -What is the calculated F statistic for blocks?

Find Tukey's simultaneous 95 percent confidence interval for $\mu _ { 1 } - \mu _ { 2 }$ where $\bar { x } _ { 1 }$ = 51.5, $\bar { x } _ { 2 }$ = 55.8,and MSE = 6.125.There were 4 treatments and 24 observations in total and the number of observations were equal in each group.

When computing Tukey simultaneous confidence intervals for all possible pairwise comparisons of the treatment group means,the experimentwise error rate will be

When computing individual confidence intervals based on the t distribution for all possible pairwise comparisons of the treatment group means,the experimentwise error rate will be

In performing a two-way ANOVA for a two-factor factorial experiment under which of the following circumstances would we test the significance of the main effects?

Test H₀: there is no interaction between Factor I and Factor II at a =.05.

Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments). Source Sum of Squares Treatments 15.93 Blocks 42.09 Error 23.84 Total 81.86 -Test H₀: there is no difference between treatment effects at a =.05.

When using a randomized block design,each block is used exactly once to measure the effect of each and every treatment.

In performing a two-way ANOVA for a two-factor factorial experiment,the error sum of squares,SSE,equals:

In performing a two-way ANOVA for a two-factor factorial experiment,we first test the _________.

The advantage of the randomized block design over the completely randomized design is that we are comparing the treatments by using ________ experimental units.

An Introduction to Business Statistics

Descriptive Statistics

Probability

Discrete Random Variables

Continuous Random Variables

Sampling Distributions

Confidence Intervals

Hypothesis Testing

Statistical Inferences Based on Two Samples

Correlation Coefficient and Simple Linear Regression Analysis

Multiple Regression and Model Building

Nonparametric Methods

Chi-Square Tests

Decision Theory

Time Series Forecasting

Filters

Exam 10: Experimental Design and Analysis of Variance

Determine degrees of freedom treatment,degrees of freedom error,and degrees of freedom total and state the critical value of the F statistic at a = .05

In one-way ANOVA,the denominator of the F statistic is an estimate of the constant population variance of the treatment groups.

In performing a two-way ANOVA for a two-factor factorial experiment,the interaction sum of squares,SS(int),equals:

A completely randomized design with three groups,each with five measurements.The one-way ANOVA yields a between-groups sum of squares treatment of 17.0493 and error sum of squares of 8.028.Compute the F statistic.

Consider the following partial analysis of variance table from a randomized block design with 10 blocks and 6 groups (treatments). Source SS Treatments 2,477.53 Blocks 3,180.48 Error 11,661.38 Total -What is the error mean square?

Source SS DF MS F Factor A 2.25 .75 Factor B .95 .95 Interaction .90 3 Error .15 Total 6.5 23 -Given the partial ANOVA table above,the number of levels of factor A are ____ and the number of levels factor B are ___.

Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments). Source Sum of Squares Treatments 15.93 Blocks 42.09 Error 23.84 Total 81.86 -What is the calculated F statistic for blocks?

When computing Tukey simultaneous confidence intervals for all possible pairwise comparisons of the treatment group means,the experimentwise error rate will be

When computing individual confidence intervals based on the t distribution for all possible pairwise comparisons of the treatment group means,the experimentwise error rate will be

In performing a two-way ANOVA for a two-factor factorial experiment under which of the following circumstances would we test the significance of the main effects?

Test H0: there is no interaction between Factor I and Factor II at a =.05.

Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments). Source Sum of Squares Treatments 15.93 Blocks 42.09 Error 23.84 Total 81.86 -Test H0: there is no difference between treatment effects at a =.05.

When using a randomized block design,each block is used exactly once to measure the effect of each and every treatment.

In performing a two-way ANOVA for a two-factor factorial experiment,the error sum of squares,SSE,equals:

In performing a two-way ANOVA for a two-factor factorial experiment,we first test the _________.

The advantage of the randomized block design over the completely randomized design is that we are comparing the treatments by using ________ experimental units.

An Introduction to Business Statistics

Descriptive Statistics

Probability

Discrete Random Variables

Continuous Random Variables

Sampling Distributions

Confidence Intervals

Hypothesis Testing

Statistical Inferences Based on Two Samples

Correlation Coefficient and Simple Linear Regression Analysis

Multiple Regression and Model Building

Nonparametric Methods

Chi-Square Tests

Decision Theory

Time Series Forecasting

Filters

Source SS DF MS F Factor A 2.25 .75 Factor B .95 .95 Interaction .90 3 Error .15 Total 6.5 23 -Given the partial ANOVA table above,the number of levels of factor A are __ and the number of levels factor B are _.

Test H₀: there is no interaction between Factor I and Factor II at a =.05.

Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments). Source Sum of Squares Treatments 15.93 Blocks 42.09 Error 23.84 Total 81.86 -Test H₀: there is no difference between treatment effects at a =.05.