Exam 10: Experimental Design and Analysis of Variance
Exam 1: An Introduction to Business Statistics63 Questions
Exam 2: Descriptive Statistics286 Questions
Exam 3: Probability177 Questions
Exam 4: Discrete Random Variables141 Questions
Exam 5: Continuous Random Variables167 Questions
Exam 6: Sampling Distributions119 Questions
Exam 7: Confidence Intervals226 Questions
Exam 8: Hypothesis Testing192 Questions
Exam 9: Statistical Inferences Based on Two Samples168 Questions
Exam 10: Experimental Design and Analysis of Variance155 Questions
Exam 11: Correlation Coefficient and Simple Linear Regression Analysis190 Questions
Exam 12: Multiple Regression and Model Building222 Questions
Exam 13: Nonparametric Methods112 Questions
Exam 14: Chi-Square Tests101 Questions
Exam 15: Decision Theory97 Questions
Exam 16: Time Series Forecasting152 Questions
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In performing a two-way ANOVA for a two-factor factorial experiment,the total sum of squares,SST equals:
(Multiple Choice)
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Source d.f. Sum of Squares Model 3 213.88125 Error 20 11.208333 Total 23 225.0895
-Consider the above one-way ANOVA table.If there are an equal number of observations in each group,then each group (treatment level)consists of ______ observations.
(Multiple Choice)
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Block 1 2 3 4 5 Tr1 2 1 2 3 2 Tr2 4 4 1 1 2.5 TR3 3 4 3 2 3 Mean 2 3 3 2 overall mean =2.5
Consider the randomized block design with 4 blocks and 3 treatments (groups) given above
-What is the block sum of squares?
(Essay)
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In a one-way ANOVA for a completely randomized design,all other things being held constant,as the sample treatment group means get closer to each other the probability of rejecting the null hypothesis decreases.
(True/False)
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Consider the following calculations for a one-way analysis of variance from a completely randomized design with 4 groups and 5 observations per group.The response variable is sales in millions of dollars and four groups represent the four regions that the company serves.
MSE = 101.25, = 33, = 43, = 49, = 28
-Compute an individual 95% confidence interval for the second group mean.
(Essay)
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We reject H0: there is no difference between the four group means at a =.05.Compute the Tukey simultaneous 95% confidence interval for all possible pairs of the groups and interpret the result.
(Essay)
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Block 1 2 3 4 5 Tr1 2 1 2 3 2 Tr2 4 4 1 1 2.5 TR3 3 4 3 2 3 Mean 2 3 3 2 overall mean =2.5
Consider the randomized block design with 4 blocks and 3 treatments (groups) given above
-What is the between-groups (or treatment)sum of squares?
(Essay)
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In a two-way ANOVA,we must test for ________ between factor 1 and factor 2 prior to testing the significance of the main effects.
(Short Answer)
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In a ___________________ experimental design,independent random samples of experimental units are assigned to the groups.
(Short Answer)
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In performing a one-way ANOVA for a completely randomized design,the _________ mean square measures the variability of the group means.
(Short Answer)
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Source SS DF MS F Factor A 2.25 .75 Factor B .95 .95 Interaction .90 3 Error .15 Total 6.5 23
-Given the partial ANOVA table above,the calculated value of the F statistic for the interaction term is ____.
(Multiple Choice)
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Block 1 2 3 4 5 Tr1 2 1 2 3 2 Tr2 4 4 1 1 2.5 TR3 3 4 3 2 3 Mean 2 3 3 2 overall mean =2.5
Consider the randomized block design with 4 blocks and 3 treatments (groups) given above
-What is the between-groups mean square?
(Essay)
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In a one-way ANOVA for a completely randomized design,all other things being held constant,as the between-treatment variation decreases,the probability of rejecting the null hypothesis increases.
(True/False)
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In a one-way analysis of variance for a completely randomized design with three treatments groups,each with five measurements,what are the degrees of freedom associated with the between-groups sum of squares?
(Multiple Choice)
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_____ simultaneous confidence intervals test all of the pairwise differences between means respectively while controlling the overall Type I error.
(Essay)
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A machine manufacturer conducted a study to compare the performance of two types of similar machines A and B in terms of the hardness of the product manufactured.According to the production supervisor,the machine setting (high,medium,low)also affects the hardness of the product.The hardness readings (response variable)are given in a two-factor factorial design format with two observations per cell. Machine type Machine Setting A B Low 8 4 8 4 Medium 7 5 6 2 High 9 4 10 5 You are also given the following additional information:
SS (machine type)= 48,SS (machine setting)= 8,SST = 64
-Determine degrees of freedom treatment,degrees of freedom error and degrees of freedom total and state the critical value of the F statistic at a = .05.
(Essay)
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In one-way ANOVA,the numerator degrees of freedom equals the number of treatment groups.
(True/False)
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Is there a significant difference in the average fill amounts of the four machines?
(Essay)
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After rejecting the null hypothesis of equal means between three treatment groups,a researcher computes Tukey simultaneous 95% confidence intervals for the difference between each pair of treatments.If all of the confidence intervals exclude the value zero,then at
= 0.05 we can conclude that there are significant differences between all pairs of treatment group means.
(True/False)
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Source SS DF MS F Factor A 2.25 .75 Factor B .95 .95 Interaction .90 3 Error .15 Total 6.5 23
-Given the partial ANOVA table above,the calculated value of the F statistic for Factor A is ____.
(Multiple Choice)
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