Exam 10: Experimental Design and Analysis of Variance

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In a one-way analysis of variance for a completely randomized design with three treatments groups,each with five measurements,what are the degrees of freedom associated with the error sum of squares?

(Multiple Choice)
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We reject H0: there is no difference between effects of levels of factor I at a =.05.Compute the Tukey simultaneous 95% confidence interval for all possible pairs of the levels of factor I and interpret the result.You are given that MSE = 1.2222.

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The 95% individual confidence interval for μ1μ2\mu _ { 1 } - \mu _ { 2 } will always be narrower than the Tukey 95% simultaneous confidence interval for μ1μ2\mu _ { 1 } - \mu _ { 2 } .

(True/False)
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Consider a two-factor factorial experiment with 4 levels of factor 1,5 levels of factor 2,and 3 observations per cell.If we use a two-way ANOVA to analyze the data from this experiment,the error degrees of freedom is:

(Multiple Choice)
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When computing a confidence interval for the difference between two means,the width of the 100(1 - α\alpha )% Tukey simultaneous confidence interval will be __________ the width of the 100(1 - α\alpha )% individual confidence interval based on the t distribution.

(Multiple Choice)
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Consider the following data from a two-factor factorial experiment.You wish to perform a two-way analysis of variance to analyze the data. Factor I Factor II 1 2 3 1 4 8 5 6 7 5 5 5 6 2 4 5 0 2 3 1 3 2 1 -What is the degrees of freedom for factor I?

(Essay)
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Consider the following data from a two-factor factorial experiment.You wish to perform a two-way analysis of variance to analyze the data. Factor I Factor II 1 2 3 1 4 8 5 6 7 5 5 5 6 2 4 5 0 2 3 1 3 2 1 -What is the factor I mean square?

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The F-test for testing the difference between group means is equal to the _____________ mean squares divided by the ___________ mean square.

(Short Answer)
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Block 1 2 3 4 5 Tr1 2 1 2 3 2 Tr2 4 4 1 1 2.5 TR3 3 4 3 2 3 Mean 2 3 3 2 overall mean =2.5 Consider the randomized block design with 4 blocks and 3 treatments (groups) given above -What is the error mean square?

(Essay)
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A machine manufacturer conducted a study to compare the performance of two types of similar machines A and B in terms of the hardness of the product manufactured.According to the production supervisor,the machine setting (high,medium,low)also affects the hardness of the product.The hardness readings (response variable)are given in a two-factor factorial design format with two observations per cell. Machine type Machine Setting A B Low 8 4 8 4 Medium 7 5 6 2 High 9 4 10 5 You are also given the following additional information: SS (machine type)= 48,SS (machine setting)= 8,SST = 64 -Determine SS(int)and SSE.

(Essay)
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Find an individual 95 percent confidence interval for μ1μ2\mu _ { 1 } - \mu _ { 2 } where xˉ1\bar { x } _ { 1 } = 33.98, xˉ2\bar { x } _ { 2 } = 36.56,and MSE = 0.669.There were 15 observations in total and 3 treatments.Assume that the number of observations in each treatment is equal.

(Essay)
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Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments). Source Sum of Squares Treatments 15.93 Blocks 42.09 Error 23.84 Total 81.86 -What is the treatment mean square?

(Essay)
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A researcher has used a one-way analysis of variance model to test whether the average starting salaries differ among the recent graduates from nursing, engineering, business and education disciplines. The researcher has randomly selected four graduates from each of the four areas. -If MSE = 4,and SST = 120 complete the following ANOVA table and determine the value of the F statistic.Note that "group" has been labeled as "treatment".

(Essay)
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Test H0: there is no difference between group (treatment)effects at a = .05.State the F value and make your decision.

(Essay)
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Consider the following partial analysis of variance table from a randomized block design with 10 blocks and 6 groups (treatments). Source SS Treatments 2,477.53 Blocks 3,180.48 Error 11,661.38 Total -Determine the degrees of freedom for the blocks.

(Essay)
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Block 1 2 3 4 5 Tr1 2 1 2 3 2 Tr2 4 4 1 1 2.5 TR3 3 4 3 2 3 Mean 2 3 3 2 overall mean =2.5 Consider the randomized block design with 4 blocks and 3 treatments (groups) given above -What is the blocks mean square?

(Essay)
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In general,a Tukey simultaneous 100(1 - α\alpha )percent confidence interval is _____ than the corresponding individual 100(1 - α\alpha )percent confidence interval.

(Short Answer)
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ANOVA table Source SS df MS F p -value Treatment 6.000 3 1.9998 18.85 3.4E-05 Error 1.486 14 0.1061 Total 7.485 17 Post hoc analysis Tukey simultaneous comparison t-values ( ( d.f. =14) =14) Brand 3 nbsp; Brand 2 nbsp; Brand 4 nbsp; Brand 1 1.402.282.582.95 Brand 3 1.40 Brand 2 2.28 Brand 4 2.58 Brand 1 2.95 4.27 5.38 1.35 7.09 3.07 1.63 The Excel/Mega-Stat output given above summarizes the results of a one-way analysis of variance in an attempt to compare the performance characteristics of four brands of vacuum cleaners. The response variable is the amount of time it takes to clean a specific size room with a specific amount of dirt. -Use the information above and determine an individual 95% confidence interval confidence interval for μ1μ2\mu _ { 1 } - \mu _ { 2 } )The mean and sample sizes for brand 1 and brand 2 are as follows: xˉ1\bar { x } _ { 1 } = 2)95, xˉ2\bar { x } _ { 2 } = 2)28,n1 = 4 and n2 = 5.

(Multiple Choice)
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The error degrees of freedom for a randomized block design ANOVA test with 4 treatment groups and 5 blocks is:

(Multiple Choice)
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The dependent variable,the variable of interest in an experiment,is also called the ___________ variable.

(Short Answer)
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