Exam 2: Motion in One Dimension

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The speed of an object is given by ν=5.00t2+4.00t\nu = 5.00 t ^ { 2 } + 4.00 t where v is in m/s and t is in s.What is the acceleration of the object at t = 2.00 s?

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The position of a particle moving along the x axis is given by x = (21 + 22t -6.0t2)m,where t is in s.What is the average velocity during the time interval t = 1.0 s to t = 3.0 s?

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In 20 minutes,Kara ran 2.40 km on a treadmill facing due east.Relative to the gym,what were her displacement and average velocity during this time interval?

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When starting from rest at the bottom of a straight road with constant upward slope,Joan bicycles to the top 50.0 s ahead of Sally,whose travel time is 5.00 minutes.What is the ratio of Joan's acceleration to Sally's acceleration?

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A rock is thrown downward from an unknown height above the ground with an initial speed of 10 m/s.It strikes the ground 3.0 s later.Determine the initial height of the rock above the ground.

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A particle starts from rest at xi = 0 and moves for 10 s with an acceleration of +2.0 cm/s2.For the next 20 s,the acceleration of the particle is -1.0 cm/s2.What is the position of the particle at the end of this motion?

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A swimmer swims 20 laps in a north-south facing pool in 7.00 minutes.Her first lap is toward the north.Her displacement and average velocity are

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Two children start at one end of a street,the origin,run to the other end,then head back.On the way back Joan is ahead of Mike.Which statement is correct about the distances run and the displacements from the origin?

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The equation that solves a problem is (18ms)2(0ms)2=2(3.0ms2)(3.0 m)\left( 18 \frac { \mathrm { m } } { \mathrm { s } } \right) ^ { 2 } - \left( 0 \frac { \mathrm { m } } { \mathrm { s } } \right) ^ { 2 } = 2 \left( 3.0 \frac { \mathrm { m } } { \mathrm { s } ^ { 2 } } \right) ( 3.0 \mathrm {~m} ) .The problem is:

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Starting from rest,a car travels 1 350 meters in 1.00 minute.It accelerated at 1.0 m/s2 until it reached its cruising speed.Then it drove the remaining distance at constant velocity.What was its cruising speed?

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The graph below shows the velocity versus time graph for a ball.Which explanation best fits the motion of the ball as shown by the graph? The graph below shows the velocity versus time graph for a ball.Which explanation best fits the motion of the ball as shown by the graph?

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An automobile manufacturer claims that its product will,starting from rest,travel 0.40 km in 9.0 s.What is the magnitude of the constant acceleration required to do this?

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The equation that solves a problem is 6.4 m=20 m+3.0ms(2.0 s)4.9ms2(2.0 s)26.4 \mathrm {~m} = 20 \mathrm {~m} + 3.0 \frac { \mathrm { m } } { \mathrm { s } } ( 2.0 \mathrm {~s} ) - 4.9 \frac { \mathrm { m } } { \mathrm { s } ^ { 2 } } ( 2.0 \mathrm {~s} ) ^ { 2 } .The problem is:

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The position of a particle as it moves along the x axis is given by x = 15e - 2t m,where t is in s.What is the acceleration of the particle at t = 1.0 s?

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The small circles in the diagram below represent the positions along the x axis of a body at equal time intervals.Assume the body moves in a straight line. The small circles in the diagram below represent the positions along the x axis of a body at equal time intervals.Assume the body moves in a straight line.   This diagram is most likely to describe This diagram is most likely to describe

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An object is thrown vertically and has an upward velocity of 18 m/s when it reaches one fourth of its maximum height above its launch point.What is the initial (launch)speed of the object?

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A car travels north at 30 m/s for one half hour.It then travels south at 40 m/s for 15 minutes.The total distance the car has traveled and its displacement are:

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A car originally traveling at 30 m/s manages to brake for 5.0 seconds while traveling 125 m downhill.At that point the brakes fail.After an additional 5.0 seconds it travels an additional 150 m down the hill.What was the acceleration of the car after the brakes failed?

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In 2.0 s,a particle moving with constant acceleration along the x axis goes from x = 10 m to x = 50 m.The velocity at the end of this time interval is 10 m/s.What is the acceleration of the particle?

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When Jim and Rob ride bicycles,Jim can only accelerate at three quarters the acceleration of Rob.Both start from rest at the bottom of a long straight road with constant upward slope.If Rob takes 5.0 minutes to reach the top,how much earlier should Jim start to reach the top at the same time as Rob?

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