Exam 12: Management and Planning Tools
Exam 1: Introduction to Quality Improvement8 Questions
Exam 2: Lean Enterprise7 Questions
Exam 3: Six Sigma10 Questions
Exam 4: Statistical Process Control6 Questions
Exam 5: Fundamentals of Statistics14 Questions
Exam 6: Control Charts for Variables17 Questions
Exam 7: Additional Spc Techniques for Variables7 Questions
Exam 8: Fundamentals of Probability11 Questions
Exam 9: Control Charts for Attributes16 Questions
Exam 10: Acceptance Sampling16 Questions
Exam 11: Reliability17 Questions
Exam 12: Management and Planning Tools11 Questions
Exam 13: Experimental Design16 Questions
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Determine the confidence interval for 10 observations with an average of 9.0 and a variance of 2.0 for 95% confidence. The t value for 0.025 is 2.262.
Free
(Short Answer)
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Correct Answer:
7.85 - 10.15
The technique that uses the positive and negative aspects of a situation to reinforce the positives and reduce or eliminate the negatives is called:
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(Multiple Choice)
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Correct Answer:
D
The technique that allows the team to generate a large number of issues/ideas and logical group them for effective problem solving is called:
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(Multiple Choice)
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Correct Answer:
D
The technique that allows the team to schedule a project efficiently is called:
(Multiple Choice)
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The technique that allows the team to classify the cause and effect factors in order for the key drivers and outcomes to help solve the problem is called:
(Multiple Choice)
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The technique that avoids surprises and proposes countermeasures is called:
(Multiple Choice)
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The technique that provides for issue/idea input from everyone on the team for effective decisions is called:
(Multiple Choice)
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An improved process has been developed to increase yield. Data from the existing process is n = 8, y-bar = 7.6, and s2 = 2.1 and the improved process is n = 6, y-bar = 8.0, and s2 = 1.5. Is the improved process better at the 0.05 level with a critical value of 1.782.
(Short Answer)
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A two factor experiment is developed with SS results for 8 values are as follows:Factor A = 40, Factor B = 120, Factor AB = 60, Total SS = 268. Determine the ANOVA and test significance against a critical value for 5% risk of 5.59.
(Short Answer)
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The technique that allows individuals or teams to identify, analyze, and rate the relationship between two or more variables is called:
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