Exam 4: Linear Systems

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Sobeys sells fruit trays consisting of pineapple and melons. The manager of the fruit department obtains pineapples at a wholesale price of $2.50 per kg, grapes at $2.15 per kg, strawberries at $1.50 per kg and melons at $1.85 per kg. He is required to produce 10 kg of the mixed fruit. He is required to add 2 kg of strawberries and 3 kg of grapes. What is the maximum weight of pineapple that he can put in the mix in order to have an effective wholesale cost no greater than $2.00 per kg?

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Cost of 2 kg of strawberries = $1.50 × 2 = $3.00
Cost of 3 kg of grapes = $2.15 × 3 = $6.45
Total cost of the mixed fruit = $2 × 10 = $20
Cost of pineapple and melons = $20 - ($3 + $6.45) = $10.55 ⇒ 2.5p + 1.85m = 10.55
Maximum weight of pineapple and melons = 10 - (2 + 3) = 5kg ⇒ p + m = 5
2.5p + 1.85m = 10.55 Cost of 2 kg of strawberries = $1.50 × 2 = $3.00 Cost of 3 kg of grapes = $2.15 × 3 = $6.45 Total cost of the mixed fruit = $2 × 10 = $20 Cost of pineapple and melons = $20 - ($3 + $6.45) = $10.55 ⇒ 2.5p + 1.85m = 10.55 Maximum weight of pineapple and melons = 10 - (2 + 3) = 5kg ⇒ p + m = 5 2.5p + 1.85m = 10.55   0.65p = 10.55 - 9.25      = 2   0.65p = 10.55 - 9.25
Cost of 2 kg of strawberries = $1.50 × 2 = $3.00 Cost of 3 kg of grapes = $2.15 × 3 = $6.45 Total cost of the mixed fruit = $2 × 10 = $20 Cost of pineapple and melons = $20 - ($3 + $6.45) = $10.55 ⇒ 2.5p + 1.85m = 10.55 Maximum weight of pineapple and melons = 10 - (2 + 3) = 5kg ⇒ p + m = 5 2.5p + 1.85m = 10.55   0.65p = 10.55 - 9.25      = 2   Cost of 2 kg of strawberries = $1.50 × 2 = $3.00 Cost of 3 kg of grapes = $2.15 × 3 = $6.45 Total cost of the mixed fruit = $2 × 10 = $20 Cost of pineapple and melons = $20 - ($3 + $6.45) = $10.55 ⇒ 2.5p + 1.85m = 10.55 Maximum weight of pineapple and melons = 10 - (2 + 3) = 5kg ⇒ p + m = 5 2.5p + 1.85m = 10.55   0.65p = 10.55 - 9.25      = 2   = 2
Cost of 2 kg of strawberries = $1.50 × 2 = $3.00 Cost of 3 kg of grapes = $2.15 × 3 = $6.45 Total cost of the mixed fruit = $2 × 10 = $20 Cost of pineapple and melons = $20 - ($3 + $6.45) = $10.55 ⇒ 2.5p + 1.85m = 10.55 Maximum weight of pineapple and melons = 10 - (2 + 3) = 5kg ⇒ p + m = 5 2.5p + 1.85m = 10.55   0.65p = 10.55 - 9.25      = 2

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