Exam 27: Circuits

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A battery of emf 24 V is connected to a 6- Ω\Omega resistor.As a result, current of 3 A exists in the resistor.The terminal potential difference of the battery is:

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D

Resistor 1 has twice the resistance of resistor 2.The two are connected in parallel and a potential difference is maintained across the combination.The rate of thermal energy dissipation in 1 is:

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C

Four 20- Ω\Omega resistors are connected in series and the combination is connected to a 20-V emf device.The current in any one of the resistors is:

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A

The circuit shown was wired for the purpose of measuring the resistance of the lamp L.Inspection shows that: The circuit shown was wired for the purpose of measuring the resistance of the lamp L.Inspection shows that:

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In the diagrams, all light bulbs are identical and all emf devices are identical.In which circuit (I, II, III, IV, V)will the bulbs glow with the same brightness as in circuit X? In the diagrams, all light bulbs are identical and all emf devices are identical.In which circuit (I, II, III, IV, V)will the bulbs glow with the same brightness as in circuit X?

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In the figure, voltmeter V1 reads 600 V, voltmeter V2 reads 580 V, and ammeter A reads 100 A.The power wasted in the transmission line connecting the power house to the consumer is: In the figure, voltmeter V<sub>1</sub> reads 600 V, voltmeter V<sub>2</sub> reads 580 V, and ammeter A reads 100 A.The power wasted in the transmission line connecting the power house to the consumer is:

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Two identical batteries, each with an emf of 18 V and an internal resistance of 1 Ω\Omega , are wired in parallel by connecting their positive terminals together and connecting their negative terminals together.The combination is then wired across a 4- Ω\Omega resistor.The current in each battery is:

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A 120-V power line is protected by a 15-A fuse.What is the maximum number of 120 V, 500 W light bulbs that can be operated at full brightness from this line?

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The resistance of resistor 1 is twice the resistance of resistor 2.The two are connected in series and a potential difference is maintained across the combination.Then:

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Here is a loop equation: Here is a loop equation:   .What does this equation represent? .What does this equation represent?

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Resistances of 2.0 Ω\Omega , 4.0 Ω\Omega , and 6.0 Ω\Omega and a 24-V battery are all in series.The current in the 2.0 Ω\Omega resistor is:

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A 3- Ω\Omega and a 1.5- Ω\Omega resistor are wired in parallel and the combination is wired in series to a 4- Ω\Omega resistor and a 10-V emf device.The potential difference across the 3- Ω\Omega resistor is:

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A battery is connected across a parallel combination of two identical resistors.If the potential difference across the terminals is V and the current in the battery is i, then:

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A 3- Ω\Omega and a 1.5- Ω\Omega resistor are wired in parallel and the combination is wired in series to a 4- Ω\Omega resistor and a 10-V emf device.The current in the 3- Ω\Omega resistor is:

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In the capacitor discharge formula q = q0e-t/RC the symbol t represents:

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A certain capacitor, in series with a 720- Ω\Omega resistor, is being charged.At the end of 10 ms its charge is half the final value.The capacitance is about:

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The terminal potential difference of a battery is less than its emf:

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A series circuit consists of a battery with internal resistance r and an external resistor R.If these two resistances are equal (r = R)then the energy dissipated per unit time by the internal resistance r is:

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Two wires made of the same material have the same length but different diameter.They are connected in parallel to a battery.The quantity that is NOT the same for the wires is:

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A total resistance of 3.0 Ω\Omega is to be produced by combining an unknown resistor R with a 12 Ω\Omega resistor.What is the value of R and how is it to be connected to the 12 Ω\Omega resistor?

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