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At 800 K,the Equilibrium Constant,Kp,for the Following Reaction Is 3

Question 43

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At 800 K,the equilibrium constant,Kp,for the following reaction is 3.2 × 10-7. 2 H2S(g) At 800 K,the equilibrium constant,K<sub>p</sub>,for the following reaction is 3.2 × 10<sup>-7</sup>. 2 H<sub>2</sub>S(g) 2 H<sub>2</sub>(g) + S<sub>2</sub>(g) A reaction vessel at 800 K initially contains 3.00 atm of H<sub>2</sub>S.If the reaction is allowed to equilibrate,what is the equilibrium pressure of S<sub>2</sub>? A) 8.5 × 10<sup>-5</sup> atm B) 6.2 × 10<sup>-3</sup> atm C) 9.0 × 10<sup>-3</sup> atm D) 1.1 × 10<sup>-2</sup> atm E) 1.4 × 10<sup>-2</sup> atm 2 H2(g) + S2(g)
A reaction vessel at 800 K initially contains 3.00 atm of H2S.If the reaction is allowed to equilibrate,what is the equilibrium pressure of S2?


A) 8.5 × 10-5 atm
B) 6.2 × 10-3 atm
C) 9.0 × 10-3 atm
D) 1.1 × 10-2 atm
E) 1.4 × 10-2 atm

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