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Find the First Five Terms of the Sequence an=n+5n2+5a _ { n } = \frac { n + 5 } { n ^ { 2 } + 5 }

Question 242

Multiple Choice

Find the first five terms of the sequence. an=n+5n2+5a _ { n } = \frac { n + 5 } { n ^ { 2 } + 5 }


A) α1=1,α2=79,α3=47,α4=37,α5=13\alpha _ { 1 } = 1 , \alpha _ { 2 } = \frac { 7 } { 9 } , \alpha _ { 3 } = \frac { 4 } { 7 } , \alpha _ { 4 } = \frac { 3 } { 7 } , \alpha _ { 5 } = \frac { 1 } { 3 }
B) α1=1,α2=97,α3=47,α4=37,α5=3\alpha _ { 1 } = 1 , \alpha _ { 2 } = \frac { 9 } { 7 } , \alpha _ { 3 } = \frac { 4 } { 7 } , \alpha _ { 4 } = \frac { 3 } { 7 } , \alpha _ { 5 } = 3
C) α1=12,α2=97,α3=47,α4=37,α5=13\alpha _ { 1 } = \frac { 1 } { 2 } , \alpha _ { 2 } = \frac { 9 } { 7 } , \alpha _ { 3 } = \frac { 4 } { 7 } , \alpha _ { 4 } = \frac { 3 } { 7 } , \alpha _ { 5 } = \frac { 1 } { 3 }
D) α1=1,α2=97,α3=47,α4=37,α5=13\alpha _ { 1 } = 1 , \alpha _ { 2 } = \frac { 9 } { 7 } , \alpha _ { 3 } = \frac { 4 } { 7 } , \alpha _ { 4 } = \frac { 3 } { 7 } , \alpha _ { 5 } = \frac { 1 } { 3 }
E) α1=12,α2=79,α3=47,α4=37,α5=3\alpha _ { 1 } = \frac { 1 } { 2 } , \quad \alpha _ { 2 } = \frac { 7 } { 9 } , \alpha _ { 3 } = \frac { 4 } { 7 } , \alpha _ { 4 } = \frac { 3 } { 7 } , \alpha _ { 5 } = 3

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