The Weekly Demand for Your Company's Lo-Cal Mousse Is Modeled $q ( t ) = \frac { 18 e ^ { 2 t - 2 } } { 1 + e ^ { 2 t - 2 } }$

Multiple Choice

The weekly demand for your company's Lo-Cal Mousse is modeled by the equation $q ( t ) = \frac { 18 e ^ { 2 t - 2 } } { 1 + e ^ { 2 t - 2 } }$ where t is time from now in weeks and q(t) is the number of gallons sold per week. Evaluate the integral $\int _ { - \infty } ^ { 0 } \frac { 18 e ^ { 2 t - 2 } } { 1 + e ^ { 2 t - 2 } } \mathrm {~d} t$ .

A) 0.254 gallons
B) 5.639 gallons
C) 2.285 gallons
D) 1.142 gallons
E) 2.819 gallons