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Find the Derivative of the Function h(x)=ln[(2x+8)(3x+6)]h ( x ) = \ln [ ( 2 x + 8 ) ( 3 x + 6 ) ]

Question 52

Multiple Choice

Find the derivative of the function. h(x) =ln[(2x+8) (3x+6) ]h ( x ) = \ln [ ( 2 x + 8 ) ( 3 x + 6 ) ]


A) 3(2x+8) 2(3x+6) \frac { 3 } { ( 2 x + 8 ) } - \frac { 2 } { ( 3 x + 6 ) }
B) 3(2x+8) +2(3x+6) \frac { 3 } { ( 2 x + 8 ) } + \frac { 2 } { ( 3 x + 6 ) }
C) 1(2x+8) +1(3x+6) \frac { 1 } { ( 2 x + 8 ) } + \frac { 1 } { ( 3 x + 6 ) }
D) 1(2x+8) 1(3x+6) \frac { 1 } { ( 2 x + 8 ) } - \frac { 1 } { ( 3 x + 6 ) }
E) 2(2x+8) +3(3x+6) \frac { 2 } { ( 2 x + 8 ) } + \frac { 3 } { ( 3 x + 6 ) }

Correct Answer:

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